go语言的匿名函数

没什么好说的， 见一个，熟悉一个：

package main

import (
"fmt"
)

func main() {
func() {
fmt.Printf("func 1 ")
}()

func(x int) {
fmt.Printf("func 2, x is %d ", x)
}(2)

a := func(x int) int {
fmt.Printf("func 3, x is %d ", x)
return 5
}
fmt.Println(a(3))

fmt.Printf("%T ", func() {
fmt.Printf("func 1 ")
})

fmt.Printf("%T ", func(x int) {
fmt.Printf("func 2, x is %d ", x)
})

fmt.Printf("%T ", a)
}
结果：

func 1
func 2, x is 2
func 3, x is 3
5
func()
func(int)
func(int) int

继续看：

package main

import (
"fmt"
)

func main() {
test(func(x string) {
fmt.Println(x)
})
}

func test(f func(string)) {
f("hello")
}
结果：hello

但如下都错误， 想想为什么：

package main

import (
"fmt"
)

func main() {
func() {
fmt.Printf("func 1 ")
}
}
package main

import (
"fmt"
)

func main() {
test(func g(x string) {
fmt.Println(x)
})
}

func test(f func(string)) {
f("hello")
}

最后， 看看下面三个正确程序的:

package main

import (
"fmt"
)

var x = "hello"

func main() {
test(func (x *string) {
*x = "world"
})

fmt.Println(x)
}

func test(f func(*string)) {
}
package main

import (
"fmt"
)

func main() {
var s1 = "hello"
var s2 = "world"

test(func(x *string, y *string) {
*x += "_123"
*y += "_456"
}, &s1, &s2)

fmt.Println(s1, s2) // hello_123 world_456
}

func test(f func(*string, *string), s1 *string, s2 *string) {
f(s1, s2)
}
package main

import (
"fmt"
)

var s1 = "hello"
var s2 = "world"

func main() {
test(func(x *string, y *string) {
*x += "_123"
*y += "_456"
})

fmt.Println(s1, s2) // hello_123 world_456
}

func test(f func(*string, *string)) {
f(&s1, &s2)
}
不多说。