多校8 1008 Clock

Clock

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 1320    Accepted Submission(s): 601

Problem Description

Give a time.(hh:mm:ss)，you should answer the angle between any two of the minute.hour.second hand
Notice that the answer must be not more 180 and not less than 0

 

Input

There are T(1≤T≤104) test cases
for each case,one line include the time

0≤hh<24,0≤mm<60,0≤ss<60

 

Output

for each case,output there real number like A/B.(A and B are coprime).if it's an integer then just print it.describe the angle between hour and minute,hour and second hand,minute and second hand.

 

Sample Input

4 00:00:00 06:00:00 12:54:55 04:40:00

 

Sample Output

0 0 0 180 180 0 1391/24 1379/24 1/2 100 140 120

Hint

每行输出数据末尾均应带有空格

#include <stdio.h>

int main()
{
    int T;
    int i,j,k,t;
    char s[10];
    scanf("%d",&T);
    while(T--)
    {
        t=0;
        scanf("%s",s);
        t=t+(s[7]-'0')+(s[6]-'0')*10;
        t=t+((s[4]-'0')+(s[3]-'0')*10)*60;
        t=t+((s[1]-'0')+(s[0]-'0')*10)*3600;
        //printf("t:%d
",t);
        int a,A,b,B,c;
        c=(t*6)%360;
        b=t%3600,B=10;
        a=t%(120*360),A=120;
        //printf("a:%d b:%d c:%d
",a,b,c);

        int x,y;
        y=120;
        if(b*12-a>=0)
            x=b*12-a;
        else
            x=a-b*12;
        if(x>(120*180))
        {
            x=120*360-x;
        }
        if(x%120==0)
            printf("%d ",x/120);
        else
        {
            while(x%2==0 && y%2==0)
            {
                x=x/2,y=y/2;
            }
            while(x%3==0 && y%3==0)
            {
                x=x/3,y=y/3;
            }
            while(x%5==0 && y%5==0)
            {
                x=x/5,y=y/5;
            }
            printf("%d/%d ",x,y);
        }

        y=120;
        if(c*120-a>=0)
            x=c*120-a;
        else
            x=a-c*120;
        if(x>(120*180))
        {
            x=120*360-x;
        }
        if(x%120==0)
            printf("%d ",x/120);
        else
        {
            while(x%2==0 && y%2==0)
            {
                x=x/2,y=y/2;
            }
            while(x%3==0 && y%3==0)
            {
                x=x/3,y=y/3;
            }
            while(x%5==0 && y%5==0)
            {
                x=x/5,y=y/5;
            }
            printf("%d/%d ",x,y);
        }

        y=10;
        if(c*10-b>=0)
            x=c*10-b;
        else
            x=b-c*10;
        if(x>(10*180))
        {
            x=10*360-x;
        }
        //printf("x:%d
",x);
        if(x%10==0)
            printf("%d ",x/10);
        else
        {
            while(x%2==0 && y%2==0)
            {
                x=x/2,y=y/2;
            }
            while(x%5==0 && y%5==0)
            {
                x=x/5,y=y/5;
            }
            printf("%d/%d ",x,y);
        }
        printf("
");
    }
    return 0;
}