算法:C语言实现 (3)字符串的查找

#include <stdlib.h>
#include <stdio.h>

#define N 10000

int main(char argc, char* argv[])
{
    int i, j, t;

    /*
        字符串的最大长度为N, 然后查找p所指向的字符串在a串中出现过的次数
        当输入终止符ctrl+z时,终止继续读入
    */
    
    char a[N], *p = argv[1];
    for (i = 0; i < N-1; a[i] = t, i++)
        if ((t = getchar()) == EOF)
            break;
    a[i] = 0;

    for (i = 0; a[i] != 0; i++)
    {
        printf("%c",a[i]);
    }
    printf("字符串中字符个数-->%d
",i);

    for (i = 0; a[i] != 0; i++)
    {
        for (j = 0; p[j] != 0; j++)
            if (a[i+j] != p[j])
                break;
        if (p[j]==0)
            printf("%d",i);
    }
    printf("
");
    return 0;
}