Hat's Fibonacci
A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1.
F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4)
Your task is to take a number as input, and print that Fibonacci number.
OutputFor each case, output the result in a line.Sample Input
100Sample Output
4203968145672990846840663646 Note:
No generated Fibonacci number in excess of 2005 digits will be in the test data, ie. F(20) = 66526 has 5 digits.
一个数组存好几位数。
#include<stdio.h> #include<string.h> int a[10001][261]; int main() { memset(a,0,sizeof(a)); a[1][0]=1; a[2][0]=1; a[3][0]=1; a[4][0]=1; a[5][0]=4; a[6][0]=7; for(int i=7; i<10000; i++) { for(int j=0; j<=260; j++) { a[i][j]+=a[i-1][j]+a[i-2][j]+a[i-3][j]+a[i-4][j]; a[i][j+1]+=a[i][j]/100000000; a[i][j]%=100000000; } } int n; while(scanf("%d",&n)!=EOF) { int i; for(i=260;i>=0;i--) { if(a[n][i]) break; } printf("%d",a[n][i]); i--; //printf("%d ",i); for(;i>=0;i--) { printf("%.8d",a[n][i]); } printf(" "); } }