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  • hdu1250(大 数)Hat's Fibonacci

    Hat's Fibonacci

    A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1.
    F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4)
    Your task is to take a number as input, and print that Fibonacci number.

    InputEach line will contain an integers. Process to end of file.
    OutputFor each case, output the result in a line.Sample Input
    100
    Sample Output
    4203968145672990846840663646
    
    
    Note:
    
    No generated Fibonacci number in excess of 2005 digits will be in the test data, ie. F(20) = 66526 has 5 digits.
    一个数组存好几位数。
    #include<stdio.h>
    #include<string.h>
    int a[10001][261];
    int main()
    {
        memset(a,0,sizeof(a));
        a[1][0]=1;
        a[2][0]=1;
        a[3][0]=1;
        a[4][0]=1;
        a[5][0]=4;
        a[6][0]=7;
        for(int i=7; i<10000; i++)
        {
            for(int j=0; j<=260; j++)
            {
                a[i][j]+=a[i-1][j]+a[i-2][j]+a[i-3][j]+a[i-4][j];
                a[i][j+1]+=a[i][j]/100000000;
                a[i][j]%=100000000;
            }
        }
        int n;
        while(scanf("%d",&n)!=EOF)
        {
            int i;
            for(i=260;i>=0;i--)
            {
                if(a[n][i])
                    break;
            }
            printf("%d",a[n][i]);
            i--;
            //printf("%d
    ",i);
            for(;i>=0;i--)
            {
                printf("%.8d",a[n][i]);
            }
            printf("
    ");
        }
    }
    

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  • 原文地址:https://www.cnblogs.com/da-mei/p/9053349.html
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