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  • 杭电1012


    u Calculate e

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 18822    Accepted Submission(s): 8211


    Problem Description
    A simple mathematical formula for e is



    where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
     

    Output
    Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
     

    Sample Output
    n e - ----------- 0 1 1 2 2 2.5 3 2.666666667 4 2.708333333






    //杭电1012
    #include <stdio.h>
    int main (int argc, char **argv)
    {
    
        printf("n e\n");
        printf("- -----------\n");
        printf("0 1\n");
        printf("1 2\n");
        printf("2 2.5\n");
        double result = 2.5 ;
        double p = 0.5;
        for (int i = 3; i <= 9; ++ i )
        {
            p /= i;
            result += p;
            printf("%d %.9f\n", i , result);
        }
        return  0;
    }
    


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  • 原文地址:https://www.cnblogs.com/dancingrain/p/3405220.html
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