java.lang.Process 阻塞问题

关键字: java

Process 类型对象的 waitFor() 方法的时候当前线程会被阻塞掉，因为InputStream in = Process.getInputStream();或 InputStream err = Process.getErrorStream(); 这2个流中的一个会被阻塞住，所以解决的办法可以是用多线程来解决，可以参看http://www.javaworld.com/javaworld/jw-12-2000/jw-1229-traps_p.html 。

但还有另一种方法可以尝试，

Java代码

1. String[] cmds = {...};//command and arg  
2. ProcessBuilder builder = new ProcessBuilder(cmds);  
3. //both read inputstream and errstream  
4. builder.redirectErrorStream(true);  
5. Process process = builder.start();  
6. BufferedReader br = new BufferedReader(new InputStreamReader(process  
7.     .getInputStream()));  
8. String readLine = br.readLine();  
9. while (readLine != null) {  
10.    System.out.println(readLine);  
11.    readLine = br.readLine();  
12. }  
13. int resultValue = process.waitFor();  

String[] cmds = {...};//command and arg ProcessBuilder builder = new ProcessBuilder(cmds); //both read inputstream and errstream builder.redirectErrorStream(true); Process process = builder.start(); BufferedReader br = new BufferedReader(new InputStreamReader(process .getInputStream())); String readLine = br.readLine(); while (readLine != null) { System.out.println(readLine); readLine = br.readLine(); } int resultValue = process.waitFor();

builder.redirectErrorStream(true); 和BufferedReader br = new BufferedReader(new InputStreamReader(process.getInputStream())); 这样使用就可以在一个线程中执行，而保证不被阻塞住。