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  • Search a 2D Matrix系列

    1、Search a 2D Matrix

     1 class Solution {
     2 public:
     3     bool searchMatrix(vector<vector<int>>& matrix, int target) {
     4          bool res = false;
     5          int row = -1;
     6          for(int i=1; i<matrix.size(); ++i)
     7          {
     8              if(target>=matrix[i-1][0] &&target<matrix[i][0])
     9              {
    10                  row = i-1;
    11                  break;
    12              }
    13          }
    14          if(row == -1)
    15               row = matrix.size()-1;
    16         
    17          for(int j=0; j<matrix[row].size(); ++j)
    18                  if(target == matrix[row][j])
    19                         return true;
    20                  
    21          return false;   
    22     }
    23 };

    2、Search a 2D Matrix II

     1 class Solution {
     2 public:
     3     bool searchMatrix(vector<vector<int>>& matrix, int target) {
     4          if(matrix.empty() || target<matrix[0][0] )
     5                 return false;
     6          int row = matrix.size(), col = matrix[0].size();
     7          int i=row-1, j=0;
     8          while(i>=0 && j<col)
     9          {
    10               if(matrix[i][j]==target)
    11                     return true;
    12               else if(matrix[i][j]<target)
    13                         j++;
    14               else if(matrix[i][j]>target) 
    15                         i--;
    16          } 
    17          return false;  
    18     }
    19 };
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  • 原文地址:https://www.cnblogs.com/daocaorenblog/p/5530249.html
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