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  • Oracle-利用解析函数计算连续、回流

    ---最大连续交易天数
    select t2.customer_no,max(t2.co) 
    from 
    (select 
    t1.customer_no,t1.yp-t1.rn rk,count(1) co
      from (select ctd.customer_no,
                   ctd.order_time yp,
                   row_number() over(partition by ctd.customer_no order by ctd.order_time) rn
              from posp_boss.customer_trans_day ctd
              where ctd.order_time >= to_date('20180101', 'yyyymmdd')
              order by ctd.customer_no,ctd.order_time)t1
              group by t1.customer_no,t1.yp-t1.rn)t2
              group by t2.customer_no
    ---计算回流状况
    with t1 as
    (select ctd.customer_no,
                   ctd.order_time yp,
                   row_number() over(partition by ctd.customer_no order by ctd.order_time) rn
              from posp_boss.customer_trans_day ctd
              where ctd.order_time >= to_date('20180101', 'yyyymmdd')
              order by ctd.customer_no,ctd.order_time)
              
              
    select t1.customer_no,max(ceil(t2.yp-t1.yp)) ypc   
    from        
    (select t1.customer_no,t1.yp,t1.rn-1 rm
    from t1) t2
    left join t1 on t1.customer_no = t2.customer_no and t1.rn = t2.rm
    group by t1.customer_no
    ---计算回流涉及天数,商户,交易量
    with t1 as
    (select ctd.customer_no,
                   ctd.order_time yp,
                   row_number() over(partition by ctd.customer_no order by ctd.order_time) rn
              from posp_boss.customer_trans_day ctd
              where ctd.order_time >= to_date('20180101', 'yyyymmdd')
              order by ctd.customer_no,ctd.order_time)
              
    select 
    t3.ypc,
    count(distinct t3.customer_no) mt,
    sum(t4.amt) amount
    from 
    (select t1.customer_no,max(ceil(t2.yp-t1.yp)) ypc   
    from        
    (select t1.customer_no,t1.yp,t1.rn-1 rm
    from t1) t2
    left join t1 on t1.customer_no = t2.customer_no and t1.rn = t2.rm
    group by t1.customer_no)t3
    join 
    (select ctd.customer_no,
              sum(ctd.trans_amount) amt 
              from posp_boss.customer_trans_day ctd
              where ctd.order_time >= to_date('20180101', 'yyyymmdd')
              group by ctd.customer_no)t4 on t3.customer_no = t4.customer_no
    group by t3.ypc
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  • 原文地址:https://www.cnblogs.com/daoren/p/10461615.html
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