使用jQuery异步传递含复杂属性及集合属性的Model到控制器方法

Student类有集合属性Courses，如何把Student连同集合属性Courses传递给控制器方法？

    public class Student
    {
        public string StudentName { get; set; }
        public IList<Course> Courses { get; set; }
    }

    public class Course
    {
        public string CourseName { get; set; }
    }

□ 思路

在前端拼装成与Student吻合、对应的对象，再使用JSON.stringify()或$.toJSON()方法转换成json格式传递给控制器方法，使用$.toJSON()方法需要引用一个jQuery的扩展js文件。  

□ Home/Index.cshtml

@{
    ViewBag.Title = "Index";
    Layout = "~/Views/Shared/_Layout.cshtml";
}

<a id="btn" href="javascript:void(0)">走你</a>

@section scripts
{
    <script src="~/Scripts/json.js"></script>
    <script type="text/javascript">
        $(function () {
            $('#btn').click(function() {
                var arr = [];

                var obj1 = new Object();
                obj1.CourseName = "语文";
                arr.push(obj1);

                var obj2 = new Object();
                obj2.CourseName = "数学";
                arr.push(obj2);

                var student = {
                    StudentName: '小明',
                    Courses: arr
                };

                //var json = JSON.stringify(student);
                var json = $.toJSON(student);

                $.ajax({
                    url: '@Url.Action("GetStuent","Home")',
                    type: 'POST',
                    contentType: 'application/json; charset=utf-8',
                    data: json,
                    dataType: 'json',
                    success: function (data) {
                        alert(data.StudentName);
                        for (i = 0; i < data.Courses.length; i++) {
                            alert(data.Courses[i].CourseName);
                        }
                    }
                });
            });

        });
    </script>
}

 

□ HomeController

        public ActionResult Index()
        {
            return View();
        }

        [HttpPost]
        public ActionResult GetStuent(Student student)
        {
            return Json(student);
        }

 

□ 把对象转换成json格式的jQuery扩展

// From: http://www.overset.com/2008/04/11/mark-gibsons-json-jquery-updated/

(function ($) {
    m = {
        '': '\b',
        '	': '\t',
        '
': '\n',
        'f': '\f',
        '
': '\r',
        '"': '\"',
        '\': '\\'
    },
    $.toJSON = function (value, whitelist) {
        var a,          // The array holding the partial texts.
            i,          // The loop counter.
            k,          // The member key.
            l,          // Length.
            r = /["\x00-x1fx7f-x9f]/g,
            v;          // The member value.

        switch (typeof value) {
            case 'string':
                return r.test(value) ?
                '"' + value.replace(r, function (a) {
                    var c = m[a];
                    if (c) {
                        return c;
                    }
                    c = a.charCodeAt();
                    return '\u00' + Math.floor(c / 16).toString(16) + (c % 16).toString(16);
                }) + '"' :
                '"' + value + '"';

            case 'number':
                return isFinite(value) ? String(value) : 'null';

            case 'boolean':
            case 'null':
                return String(value);

            case 'object':
                if (!value) {
                    return 'null';
                }
                if (typeof value.toJSON === 'function') {
                    return $.toJSON(value.toJSON());
                }
                a = [];
                if (typeof value.length === 'number' &&
                    !(value.propertyIsEnumerable('length'))) {
                    l = value.length;
                    for (i = 0; i < l; i += 1) {
                        a.push($.toJSON(value[i], whitelist) || 'null');
                    }
                    return '[' + a.join(',') + ']';
                }
                if (whitelist) {
                    l = whitelist.length;
                    for (i = 0; i < l; i += 1) {
                        k = whitelist[i];
                        if (typeof k === 'string') {
                            v = $.toJSON(value[k], whitelist);
                            if (v) {
                                a.push($.toJSON(k) + ':' + v);
                            }
                        }
                    }
                } else {
                    for (k in value) {
                        if (typeof k === 'string') {
                            v = $.toJSON(value[k], whitelist);
                            if (v) {
                                a.push($.toJSON(k) + ':' + v);
                            }
                        }
                    }
                }
                return '{' + a.join(',') + '}';
        }
    };

})(jQuery);