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  • Django 路由系统

    单一路由对应

    from django.urls import re_path path
    
    # FBV
    re_path(r'^login.html$', views.login),
    path(r'login.html', views.login),
    # CBV
    re_path(r'^login.html$', views.Login.as_view()),
    

    基于正则的路由

    from django.urls import re_path
    
    re_path(r'^test-(d+)/', views.test),	# 以位置判断参数
    re_path(r'^url-(?P<nid>d+)-(?P<uid>d+).html', views.url),		# 以名称判断参数,建议使用这种,不受传递参数位置改变影响
    

    获取方法:

    def test1(request, page):
        print(page)
        return render(request, 'test1.html')
    
    def test2(request, **kwargs):
        print(kwargs.get('nid', None), kwargs.get('uid', None))
        return render(request, 'test2.html')
    

    添加额外的参数

    # FBV
    re_path(r'^index1.html$', views.index(参数)),
    # CBV
    re_path(r'^index1.html$', views.Index.as_view()(参数)),
    

    为路由映射设置名称

    re_path(r'^index1/', views.index, name='i1'),
    re_path(r'^index2/(d+)/(d+)/', views.index, name='i2'),
    re_path(r'^index3/(?P<pid>d+)/(?P<nid>d+)/', views.index, name='i3'),
    

    在 .py 文件中
    通过 reverse 获取 url

    from django.urls import reverse
    
    def func(request, *args, **kwargs):
    url1 = reverse('i1')                              # index1/
    url2 = reverse('i2', args=(1,2,))                 # index2/1/2/
    url3 = reverse('i3', kwargs={'pid': 1, 'nid': 9}) # index3/1/9/
    

    在 html 文件中

    {% url "i1" %}               # index1/
    {% url "i2" 1 2 %}           # index2/1/2/
    {% url "i3" pid=1 nid=9 %}   # index3/1/9/
    

    根据APP对路由规则进行分类

    project/urls.py:

    from django.conf.urls import re_path, include
    from django.contrib import admin
    
    urlpatterns = [
    	re_path(r'^app01/', include("app01.urls")),
    	re_path(r'^app02/', include("app02.urls")),
    ]
    

    app01/urls.py:

    from django.conf.urls import re_path, include
    from django.contrib import admin
    from app01 import views
    
    urlpatterns = [
    	re_path(r'^login/', views.login),
    ]
    

    app02/urls.py:

    from django.conf.urls import re_path, include
    from django.contrib import admin
    from app02 import views
    
    urlpatterns = [
    	re_path(r'^login/', views.login),
    ]
    

    默认值

    url.py:

    urlpatterns = [
    	re_path(r'^index/', views.index, {'name': 'root'}),
    ]
    

    views.py:

    def index(request, name):
    	print(name)
    	return HttpResponse('OK')
    

    命名空间

    project/urls.py:

    from django.conf.urls import re_path, include
    
    urlpatterns = [
    	re_path(r'^app01-m/', include("app01.urls", namespace='app_m')),
    	re_path(r'^app01-n/', include("app01.urls", namespace='app_n')),
    ]
    

    app01/urls.py:

    from django.conf.urls import url
    from app01 import views
    
    app_name = 'app01'
    urlpatterns = [
        url(r'^(?P<pk>d+)/$', views.test, name='detail')
    ]
    

    在 views.py 文件中

    from django.urls import reverse
    
    def test(request, **kwargs):
        pk = kwargs.get('pk', None)
        print(reverse('app01:detail', kwargs={'pk': pk}))
        print(reverse('app_m:detail', kwargs={'pk': pk}))
        print(reverse('app_n:detail', kwargs={'pk': pk}))
        print(request.resolver_match)
        return render(request, 'test.html', {'pk': pk})
    
    

    访问'/app01-m-app/1/',输出结果:

    /app01-n/1/
    /app01-m/1/
    /app01-n/1/
    ResolverMatch(func=app01.views.test, args=(), kwargs={'pk': '1'}, url_name=detail, app_names=['app01'], namespaces=['app_m'], route=^app01-m/(?P<pk>d+)/$)
    

    访问'/app01-n-app/1/',输出结果:

    /app01-n/1/
    /app01-m/1/
    /app01-n/1/
    ResolverMatch(func=app01.views.test, args=(), kwargs={'pk': '1'}, url_name=detail, app_names=['app01'], namespaces=['app_n'], route=^app01-n/(?P<pk>d+)/$)
    

    在 test.html 文件中

    {% url 'app01:detail' pk %}
    {% url 'app_m:detail' pk %}
    {% url 'app_n:detail' pk %}
    

    访问'/app01-m-app/1/',显示:

    /app01-m/1/ /app01-m/1/ /app01-n/1/
    

    访问'/app01-n-app/1/',显示:

    /app01-n/1/ /app01-m/1/ /app01-n/1/
    
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  • 原文地址:https://www.cnblogs.com/dbf-/p/10883606.html
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