1147: 零起点学算法54——Fibonacc

1147: 零起点学算法54——Fibonacc

Time Limit: 1 Sec  Memory Limit: 64 MB   64bit IO Format: %lld
Submitted: 2097  Accepted: 863
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Description

Fibonacci数列定义为（1,1,2,3,5,8,.....），即每个元素是前两个元素的和。如果一个Fibonacci数与所有小于它的Fibonacci数互质，那么称之为Fibonacci质数。
现在要求你输出前n个Fibonacci数
The Fibonacci Numbers {0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ...} are defined by the recurrence:
F(0)=0
F(1)=1
F(i)=F(i-1)+F(i-2)
Write a program to calculate the Fibonacci Numbers. 

Input

 

 The first line of the input file contains a single integer T, the number of test cases. The following T lines,each contains an integer n ( 0 <= n <= 45 ), and you are expected to calculate Fn

Output

 

 Output Fn on a separate line.

Sample Input

 

5
0
3
5
9
20

Sample Output

0
2
5
34
6765

Source

零起点学算法

 

#include<stdio.h>
int main(){
    int T,a[50]={0,1,1};
    for(int i=3;i<=45;i++){
        a[i]=a[i-1]+a[i-2];
    }
    scanf("%d",&T);
    for(int i=0;i<T;i++){
        int n;
        scanf("%d",&n);
        printf("%d
",a[n]);
    }
    return 0;
}