zoukankan      html  css  js  c++  java
  • 基于3点构建圆/弧

    # coding:utf-8
    import numpy as np
    import pandas as pd
    import geopandas as gpd
    from scipy import interpolate
    from functools import partial
    from shapely.geometry import Point, LineString
    from shapely.affinity import rotate, scale
    from shapely.ops import split, linemerge, snap
    import logging
    logging.basicConfig(level=logging.WARNING,
                        format='%(asctime)s-%(filename)s[line:%(lineno)d]-%(levelname)s:%(message)s',
                        datefmt='%Y-%m-%d %H:%M:%S')
    
    
    class arcBase3pnts():
        # 基于3点构建圆/弧
        
        def __init__(self, pnts):
            p1, p2, p3 = pnts
            self.p1 = p1
            self.p2 = p2
            self.p3 = p3
        
        def getCenterAndRadius(self):
            # pnts = [[x1,y1],[x2,y2],[x3,y3]]
            p1, p2, p3 = self.p1, self.p2, self.p3
            
            ls1, ls2 = LineString([p2, p3]), LineString([p1, p3])
            fx = partial(scale, xfact=100, yfact=100)
            ls1, ls2 = fx(ls1), fx(ls2)
            vs1, vs2 = rotate(ls1, 90), rotate(ls2, 90)
            
            cp = vs1.intersection(vs2)
            r = cp.distance(Point(p1))
            return cp, r 
                
        
        def getCircle(self):
            # pnts = [[x1,y1],[x2,y2],[x3,y3]]
            cp, r = self.getCenterAndRadius()
            
            return cp.buffer(r)
        
        def getArc(self):
            # 获取过三点的弧长
            # 要求弧长过点的顺序按照点的顺序,即中间点在弧长的中间部分
            p1, p2, p3 = self.p1, self.p2, self.p3
            circle = self.getCircle()
            ls = LineString([p1, p3])
            parts = split(circle, ls)
            logging.warning(f"[{p1},{p2},{p3}]")
            logging.warning(f"nparts:{len(parts)}")
            
            lg = [part.distance(Point(p2)) for part in parts]
            idx = np.argmin(lg)
            part = parts[idx]
            
            res = circle.boundary.intersection(part)
            tmp = []
            for i in range(len(res)):  # 处理可能出行的多线情况
                gtype = res[i].geom_type
                # logging.warning(f"gtype:{gtype}")
                if gtype == "LineString":
                    tmp.append(res[i])
            res2 = linemerge(tmp)        
            return res2
        
        def getLastArc(self):
            # 获取过后两个点之间的弧
            p2 = self.p2
            arc = self.getArc()
            pp2 = Point(p2)
            toler = np.ceil(arc.distance(pp2))
            arc = snap(arc, pp2, tolerance=toler)
            parcs = split(arc, pp2)
            index = 0 if parcs[0].distance(pp2)<parcs[0].distance(pp2) else 1
            return parcs[index]
    
    
    if __name__ == "__main__":
        
        pnts = [(13490633.7293, 4161607.44897),(13497014.3574, 4149089.65039),(13499473.5673, 4141429.48048)]
        oarc = arcBase3pnts(pnts=pnts)
        arc = oarc.getArc()
        prc = oarc.getLastArc()
  • 相关阅读:
    linux虚拟机上网
    asp 两种方法连接sql sever 并显示
    了解ado.net 的相关内库--读书笔记
    win10固态硬盘分区方法
    sql sever2012安装错误,无效的十六进制字符
    python学习笔记3
    python 学习笔记4
    python学习笔记2
    20189319《网络攻防》第十周作业
    20189319《网络攻防》第九周作业
  • 原文地址:https://www.cnblogs.com/ddzhen/p/15661564.html
Copyright © 2011-2022 走看看