zoukankan      html  css  js  c++  java
  • A2. Prefix Flip (Hard Version)

    A2. Prefix Flip (Hard Version)

    #include <iostream>
    #include <vector>
    #include <algorithm>
    #include <string>
    #include <set>
    #include <queue>
    #include <map>
    #include <sstream>
    #include <cstdio>
    #include <cstring>
    #include <numeric>
    #include <cmath>
    #include <iomanip>
    #include <deque>
    #include <bitset>
    #include <cassert>
    //#include <unordered_set>
    //#include <unordered_map>
    #define ll              long long
    #define pii             pair<int, int>
    #define rep(i,a,b)      for(ll  i=a;i<=b;i++)
    #define dec(i,a,b)      for(ll  i=a;i>=b;i--)
    #define forn(i, n)      for(ll i = 0; i < int(n); i++)
    using namespace std;
    int dir[4][2] = { { 1,0 },{ 0,1 } ,{ 0,-1 },{ -1,0 } };
    const long long INF = 0x7f7f7f7f7f7f7f7f;
    const int inf = 0x3f3f3f3f;
    const double pi = acos(-1.0);
    const double eps = 1e-6;
    const int mod = 1e9 + 7;
    
    inline ll read()
    {
        ll x = 0; bool f = true; char c = getchar();
        while (c < '0' || c > '9') { if (c == '-') f = false; c = getchar(); }
        while (c >= '0' && c <= '9') x = (x << 1) + (x << 3) + (c ^ 48), c = getchar();
        return f ? x : -x;
    }
    inline ll gcd(ll m, ll n)
    {
        return n == 0 ? m : gcd(n, m % n);
    }
    void exgcd(ll A, ll B, ll& x, ll& y)
    {
        if (B) exgcd(B, A % B, y, x), y -= A / B * x; else x = 1, y = 0;
    }
    inline int qpow(int x, ll n) {
        int r = 1;
        while (n > 0) {
            if (n & 1) r = 1ll * r * x % mod;
            n >>= 1; x = 1ll * x * x % mod;
        }
        return r;
    }
    inline int inv(int x) {
        return qpow(x, mod - 2);
    }
    /**********************************************************/
    const int N = 1e7 + 5;
    
    
    int main() {
        cin.tie(0), cout.tie(0);
        int T;
        cin >> T;
        while (T--)
        {
            int len;
            string s1, s2;
            cin >> len >> s1 >> s2;
            if (len == 1)
            {
                if (s1 == s2)
                    cout << 0 << endl;
                else
                    cout << "1 1" << endl;
                continue;
            }
            int i = 0, j = s1.size() - 1;
            for (; j >= 0 && s1[j] == '0'; j--);
            int cur = 1;
            vector<int> res;
            while (i <= j)
            {
                if (cur)
                {
                    for (; i <= j && s1[i] == '0'; i++);
                    if (i > 0)
                        res.push_back(i);
                    cur = 0;
                }
                else
                {
                    for (; i <= j && s1[i] == '1'; i++);
                    if (i > 0)
                        res.push_back(i);
                    cur = 1;
                }
            }
            cur = 1;
            i = len-1;
            while(i>0)
            {
                if (cur)
                {
                    for (; i >= 0 && s2[i] == '0'; i--);
                    if (i < len && i>=0)
                        res.push_back(i+1);
                    cur = 0;
                }
                else
                {
                    for (; i >=0  && s2[i] == '1'; i--);
                    if (i < len-1 && i>=0)
                        res.push_back(i+1);
                    cur = 1;
                }
            }
            cout << res.size() <<" ";
            forn(i, res.size())
                cout << res[i] << " ";
            cout << endl;
        }
    }
  • 相关阅读:
    Hadoopif.for.while 语句
    完全分布模式的四大模块设置
    语法糖定义
    Karaf 依赖equinox and felix,karaf 本Apache的很多项目作为基础框架
    Karaf 基于 osgi
    MEF(Managed Extensibility Framework) 微软平台插件化开发
    析构函数,构造函数
    C#和ASP.Net面试题目集锦
    论C# java的基本类型
    Boolean.parseBoolean("true") 和 Boolean.getBoolean("true");的区别及用法
  • 原文地址:https://www.cnblogs.com/dealer/p/13388629.html
Copyright © 2011-2022 走看看