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  • [LeetCode]1313. Decompress Run-Length Encoded List

    We are given a list nums of integers representing a list compressed with run-length encoding.

    Consider each adjacent pair of elements [a, b] = [nums[2*i], nums[2*i+1]] (with i >= 0).  For each such pair, there are a elements with value b in the decompressed list.

    Return the decompressed list.

    Example 1:

    Input: nums = [1,2,3,4]
    Output: [2,4,4,4]
    Explanation: The first pair [1,2] means we have freq = 1 and val = 2 so we generate the array [2].
    The second pair [3,4] means we have freq = 3 and val = 4 so we generate [4,4,4].
    At the end the concatenation [2] + [4,4,4,4] is [2,4,4,4].
     

    Constraints:

    2 <= nums.length <= 100
    nums.length % 2 == 0
    1 <= nums[i] <= 100

    来源:力扣(LeetCode)
    链接:https://leetcode-cn.com/problems/decompress-run-length-encoded-list
    著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。

    python3:

    1 class Solution:
    2     def decompressRLElist(self, nums: List[int]) -> List[int]:
    3         rst = []
    4         for i in range(len(nums)):
    5             if 0 == i % 2:
    6                 tmp = nums[i]*[nums[i + 1]] 
    7                 rst += tmp
    8         return rst
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  • 原文地址:https://www.cnblogs.com/dean757/p/12295437.html
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