35. Search Insert Position
Easy
Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You may assume no duplicates in the array.
Example 1:
Input: [1,3,5,6], 5 Output: 2
Example 2:
Input: [1,3,5,6], 2 Output: 1
Example 3:
Input: [1,3,5,6], 7 Output: 4
Example 4:
Input: [1,3,5,6], 0 Output: 0
package leetcode.easy;
public class SearchInsertPosition {
@org.junit.Test
public void test() {
int[] nums1 = { 1, 3, 5, 6 };
int target1 = 5;
int[] nums2 = { 1, 3, 5, 6 };
int target2 = 2;
int[] nums3 = { 1, 3, 5, 6 };
int target3 = 7;
int[] nums4 = { 1, 3, 5, 6 };
int target4 = 0;
System.out.println(searchInsert(nums1, target1));
System.out.println(searchInsert(nums2, target2));
System.out.println(searchInsert(nums3, target3));
System.out.println(searchInsert(nums4, target4));
}
public int searchInsert(int[] nums, int target) {
int low = 0;
int high = nums.length - 1;
while (low <= high) {
int mid = (low + high) / 2;
if (nums[mid] == target) {
return mid;
}
if (nums[mid] > target) {
high = mid - 1;
} else {
low = mid + 1;
}
}
return low;
}
}