zoukankan      html  css  js  c++  java
  • LeetCode_189. Rotate Array

    189. Rotate Array

    Easy

    Given an array, rotate the array to the right by k steps, where k is non-negative.

    Example 1:

    Input: [1,2,3,4,5,6,7] and k = 3
    Output: [5,6,7,1,2,3,4]
    Explanation:
    rotate 1 steps to the right: [7,1,2,3,4,5,6]
    rotate 2 steps to the right: [6,7,1,2,3,4,5]
    rotate 3 steps to the right: [5,6,7,1,2,3,4]
    

    Example 2:

    Input: [-1,-100,3,99] and k = 2
    Output: [3,99,-1,-100]
    Explanation: 
    rotate 1 steps to the right: [99,-1,-100,3]
    rotate 2 steps to the right: [3,99,-1,-100]
    

    Note:

    • Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.
    • Could you do it in-place with O(1) extra space?
    package leetcode.easy;
    
    public class RotateArray {
    	private static void print_arr(int[] nums) {
    		for (int num : nums) {
    			System.out.print(num + " ");
    		}
    		System.out.println();
    	}
    
    	public void rotate1(int[] nums, int k) {
    		int temp, previous;
    		for (int i = 0; i < k; i++) {
    			previous = nums[nums.length - 1];
    			for (int j = 0; j < nums.length; j++) {
    				temp = nums[j];
    				nums[j] = previous;
    				previous = temp;
    			}
    		}
    	}
    
    	public void rotate2(int[] nums, int k) {
    		int[] a = new int[nums.length];
    		for (int i = 0; i < nums.length; i++) {
    			a[(i + k) % nums.length] = nums[i];
    		}
    		for (int i = 0; i < nums.length; i++) {
    			nums[i] = a[i];
    		}
    	}
    
    	public void rotate3(int[] nums, int k) {
    		k = k % nums.length;
    		int count = 0;
    		for (int start = 0; count < nums.length; start++) {
    			int current = start;
    			int prev = nums[start];
    			do {
    				int next = (current + k) % nums.length;
    				int temp = nums[next];
    				nums[next] = prev;
    				prev = temp;
    				current = next;
    				count++;
    			} while (start != current);
    		}
    	}
    
    	public void rotate4(int[] nums, int k) {
    		k %= nums.length;
    		reverse(nums, 0, nums.length - 1);
    		reverse(nums, 0, k - 1);
    		reverse(nums, k, nums.length - 1);
    	}
    
    	public void reverse(int[] nums, int start, int end) {
    		while (start < end) {
    			int temp = nums[start];
    			nums[start] = nums[end];
    			nums[end] = temp;
    			start++;
    			end--;
    		}
    	}
    
    	@org.junit.Test
    	public void test1() {
    		int[] nums1 = { 1, 2, 3, 4, 5, 6, 7 };
    		int k1 = 3;
    		int[] nums2 = { -1, -100, 3, 99 };
    		int k2 = 2;
    		print_arr(nums1);
    		rotate1(nums1, k1);
    		print_arr(nums1);
    
    		print_arr(nums2);
    		rotate1(nums2, k2);
    		print_arr(nums2);
    	}
    
    	@org.junit.Test
    	public void test2() {
    		int[] nums1 = { 1, 2, 3, 4, 5, 6, 7 };
    		int k1 = 3;
    		int[] nums2 = { -1, -100, 3, 99 };
    		int k2 = 2;
    		print_arr(nums1);
    		rotate2(nums1, k1);
    		print_arr(nums1);
    
    		print_arr(nums2);
    		rotate2(nums2, k2);
    		print_arr(nums2);
    	}
    
    	@org.junit.Test
    	public void test3() {
    		int[] nums1 = { 1, 2, 3, 4, 5, 6, 7 };
    		int k1 = 3;
    		int[] nums2 = { -1, -100, 3, 99 };
    		int k2 = 2;
    		print_arr(nums1);
    		rotate3(nums1, k1);
    		print_arr(nums1);
    
    		print_arr(nums2);
    		rotate3(nums2, k2);
    		print_arr(nums2);
    	}
    
    	@org.junit.Test
    	public void test4() {
    		int[] nums1 = { 1, 2, 3, 4, 5, 6, 7 };
    		int k1 = 3;
    		int[] nums2 = { -1, -100, 3, 99 };
    		int k2 = 2;
    		print_arr(nums1);
    		rotate4(nums1, k1);
    		print_arr(nums1);
    
    		print_arr(nums2);
    		rotate4(nums2, k2);
    		print_arr(nums2);
    	}
    }
    
  • 相关阅读:
    20169219 实验二 Java面向对象程序设计
    20169219 2016-2017-2 《移动平台开发》第七周作业
    20169219 实验一 Java开发环境的熟悉(Linux + IDEA)
    20169219 2016-2017-2《网络攻防》第七周作业
    文件下载之ServletOutputStream
    DOM对象之window
    webservice接口的开发和调用
    utf-8与unicode是什么关系
    hibernate注解之@Onetomany、@Manytoone、@JoinColumn
    ajax不执行success的问题
  • 原文地址:https://www.cnblogs.com/denggelin/p/11697400.html
Copyright © 2011-2022 走看看