有人说主要的因素是在于JSON格式不直接支持日期和时间。
简单一点处理办法是ToLocalTime()一下:dt = dt.ToLocalTime();
参考http://blog.csdn.net/cncdns/article/details/6164389 写个jsonhelp。不直接调用JavaScriptSerializer 的序列号就能解决这个问题。
using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Runtime.Serialization.Json; using System.IO; using System.Text; using System.Text.RegularExpressions; /// <summary> /// JSON序列化和反序列化辅助类 /// </summary> public class JsonHelper { /// <summary> /// JSON序列化 /// </summary> public static string JsonSerializer<T>(T t) { DataContractJsonSerializer ser = new DataContractJsonSerializer(typeof(T)); MemoryStream ms = new MemoryStream(); ser.WriteObject(ms, t); string jsonString = Encoding.UTF8.GetString(ms.ToArray()); ms.Close(); //替换Json的Date字符串 string p = @"///Date/((/d+)/+/d+/)///"; /*////Date/((([/+/-]/d+)|(/d+))[/+/-]/d+/)////*/ MatchEvaluator matchEvaluator = new MatchEvaluator(ConvertJsonDateToDateString); Regex reg = new Regex(p); jsonString = reg.Replace(jsonString, matchEvaluator); return jsonString; } /// <summary> /// JSON反序列化 /// </summary> public static T JsonDeserialize<T>(string jsonString) { //将"yyyy-MM-dd HH:mm:ss"格式的字符串转为"//Date(1294499956278+0800)//"格式 string p = @"/d{4}-/d{2}-/d{2}/s/d{2}:/d{2}:/d{2}"; MatchEvaluator matchEvaluator = new MatchEvaluator(ConvertDateStringToJsonDate); Regex reg = new Regex(p); jsonString = reg.Replace(jsonString, matchEvaluator); DataContractJsonSerializer ser = new DataContractJsonSerializer(typeof(T)); MemoryStream ms = new MemoryStream(Encoding.UTF8.GetBytes(jsonString)); T obj = (T)ser.ReadObject(ms); return obj; } /// <summary> /// 将Json序列化的时间由/Date(1294499956278+0800)转为字符串 /// </summary> private static string ConvertJsonDateToDateString(Match m) { string result = string.Empty; DateTime dt = new DateTime(1970,1,1); dt = dt.AddMilliseconds(long.Parse(m.Groups[1].Value)); dt = dt.ToLocalTime(); result = dt.ToString("yyyy-MM-dd HH:mm:ss"); return result; } /// <summary> /// 将时间字符串转为Json时间 /// </summary> private static string ConvertDateStringToJsonDate(Match m) { string result = string.Empty; DateTime dt = DateTime.Parse(m.Groups[0].Value); dt = dt.ToUniversalTime(); TimeSpan ts = dt - DateTime.Parse("1970-01-01"); result = string.Format("///Date({0}+0800)///",ts.TotalMilliseconds); return result; } }