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  • mysql练习题99

     1 一、查询每个专业的学生人数
     2 SELECT COUNT(*)
     3 FROM student
     4 GROUP BY majorid;
     5 
     6 二、查询参加考试的学生中,每个学生的平均分、最高分
     7 SELECT avg(score),MAX(score),studentno
     8 FROM result
     9 GROUP BY stduentno;
    10 
    11 三、查询姓张的每个学生的最低分大于60的学号、姓名
    12 SELECT s.studentid,s.studentname,MIN(score)
    13 FROM student s
    14 JOIN result r
    15 on s.studentno=r.studentno
    16 where s.studentname LIKE '张%'
    17 GROUP BY studentno
    18 HAVING min(score)>60;
    19 
    20 四、查询专业生日在“1988-1-1”后的学生姓名、专业名称
    21 SELECT studentname,majorname,borndate
    22 FROM student s
    23 join major m
    24 on s.majorid=m.majorid
    25 where DATEDIFF(borndate,'1988-1-1')>0;
    26 
    27 #五、查询每个专业的男生人数和女生人数分别是多少
    28 #方式一:
    29 SELECT COUNT(*) 个数,majorid,sex
    30 FROM student
    31 GROUP BY sex,majorid;
    32 
    33 方式二:
    34 SELECT majorid,
    35 (SELECT COUNT(*) FROM student where sex='' and majorid=s.majorid) 男,
    36 (SELECT COUNT(*) FROM student where sex='' and majorid=s.majorid) 女
    37 FROM student s
    38 GROUP BY majorid 
    39 
    40 
    41 六、查询专业和张翠山一样的学生的最低分
    42 SELECT MIN(score)
    43 FROM result
    44 where studentno in (
    45 SELECT studentno
    46 FROM student
    47 WHERE mojorid=(SELECT majorid
    48 FROM student 
    49 where studentname='张翠山'));
    50 
    51 七、查询大于60分的学生的姓名、密码、专业名
    52 SELECT studentname,loginpwd,majorname
    53 FROM student  s
    54 join result r
    55 on s.studentno=r.studentno
    56 JOIN major m
    57 on s.majorid=m.majorid
    58 where r.score>60;
    59 
    60 八、按邮箱位数分组,查询每组的学生个数
    61 SELECT COUNT(*)
    62 FROM student
    63 GROUP BY LENGTH(email);
    64 
    65 九、查询学生名、专业名、分数
    66 SELECT studentname,majorname,score
    67 FROM student s
    68 JOIN major m
    69 on s.majorid=m.majorid
    70 JOIN s.studentno=r.studentno;
    71 
    72 十、查询哪个专业没有学生,分别用左连接和右连接实现
    73 SELECT majorid,majorname
    74 from major m
    75 LEFT JOIN student s
    76 on m.majorid=s.majorid
    77 where s.studentno is null
    78 
    79 十一、查询没有成绩的学生人数
    80 SELECT COUNT(*)
    81 FROM student s
    82 LEFT JOIN result r on s.studentno=r.studentno
    83 where r.id is null
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  • 原文地址:https://www.cnblogs.com/deyo/p/13287305.html
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