C#事物处理

对两个数据表同时进行insert操作处理，对它们的插入操作要么全部成功，要么都插入失败，否则只插入一个表成功会引起数据库的不一致。很显然，这是一个事务处理(transcation)，要么commit成功，要么则rollback。在代码中，利用C#中提供的Transcation类来实现，代码如下：

        private void btn_submit_Click(object sender, System.EventArgs e)
        {
            string strconn = ConfigurationSettings.AppSettings["dsn"];
            SqlConnection cnn = new SqlConnection(strconn);
            SqlCommand cmd = new SqlCommand();
            SqlTransaction transaction = null;

            try
            {
                cnn.Open();
                // 先插入分店shop表，再插入经理Manager表，并将其作为一个事务进行处理
                transaction = cnn.BeginTransaction();
                cmd.Transaction = transaction;
                cmd.Connection = cnn;

                // 插入分店shop表
                string shopstr = "insert into shop values('" + tbx_shopid.Text + "','" + tbx_shopname.Text + "','" + tbx_shopaddress.Text + "','" + tbx_shopphone.Text + "')";
                cmd.CommandType = CommandType.Text;
                cmd.CommandText = shopstr;
                cmd.ExecuteNonQuery();

                // 插入经理Manager表
                string managerstr = "insert into manager values('" + tbx_managerid.Text + "','" + tbx_managerpassword.Text + "','" + tbx_managername.Text + "','" + tbx_shopid.Text + "')";
                cmd.CommandType = CommandType.Text;
                cmd.CommandText = managerstr;
                cmd.ExecuteNonQuery();

                // 提交事务
                transaction.Commit();
                lbl_msg.Text = "添加分店操作成功";
            }
            catch(Exception ex)
            {
                lbl_msg.Text = "添加分店操作失败";
                transaction.Rollback();
            }
            finally
            {
                cnn.Close();
            }
        }