zoukankan      html  css  js  c++  java
  • LeetCode OJ

    题目:

    Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.

    An example is the root-to-leaf path 1->2->3 which represents the number 123.

    Find the total sum of all root-to-leaf numbers.

    For example,

        1
       / 
      2   3
    

    The root-to-leaf path 1->2 represents the number 12.
    The root-to-leaf path 1->3 represents the number 13.

    Return the sum = 12 + 13 = 25.

    解题思路:

    利用深搜找到所有路径上表示的数,然后把它们加起来。

    代码:

    /**
     * Definition for binary tree
     * struct TreeNode {
     *     int val;
     *     TreeNode *left;
     *     TreeNode *right;
     *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     * };
     */
    class Solution {
    public:
        void dfs(TreeNode *root, int cur_ans, int &ans) {
            if (root == NULL) return;
            
            if (root->left == NULL && root->right == NULL) ans += (cur_ans * 10 + root->val);
            if (root->left != NULL) dfs(root->left, cur_ans * 10 + root->val, ans);
            if (root->right != NULL) dfs(root->right, cur_ans * 10 + root->val, ans);
            return;
        }
        int sumNumbers(TreeNode *root) {
            int ans = 0;
            dfs(root, 0, ans);
            
            return ans;
        }
    };
  • 相关阅读:
    iOS 添加微信分享
    IOS学习笔记——ViewController生命周期详解
    UI之CALayer详解(转)
    iOS CALayer讲解
    [leetcode] Minimum Path Sum
    [leetcode]Binary Tree Maximum Path Sum
    我是真的想去google啊
    C++ string 用法详解
    继续存博客
    bash中 2>&1 & 的解释
  • 原文地址:https://www.cnblogs.com/dongguangqing/p/3727313.html
Copyright © 2011-2022 走看看