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  • LeetCode OJ

    题目:

    Given two binary trees, write a function to check if they are equal or not.

    Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

    解题思路:

    递归求解。先判断根,然后递归判断左子树和右子树

    代码

     1 /**
     2  * Definition for binary tree
     3  * struct TreeNode {
     4  *     int val;
     5  *     TreeNode *left;
     6  *     TreeNode *right;
     7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     8  * };
     9  */
    10 class Solution {
    11 public:
    12     bool isSameTree(TreeNode *p, TreeNode *q) {
    13         if (p == NULL && q == NULL){
    14             return true;
    15         }
    16         else if (p != NULL && q != NULL && p->val == q->val ){
    17             return isSameTree(p->left, q->left) && isSameTree(p->right, q->right);
    18         } else {
    19             return false;
    20         }
    21     }
    22 };
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  • 原文地址:https://www.cnblogs.com/dongguangqing/p/3737232.html
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