zoukankan      html  css  js  c++  java
  • No function matches the given name and argument types. You might need to add explicit type casts postgrepsql数据库

    今天在写项目的时候,遇到了一个比价头疼的问题:

    ifnull.............

    No function matches the given name and argument types. You might need to add explicit type casts

    现在公司用的是postgrepsql数据库,自己用navicat连接的,屁颠屁颠的还当是mysql的函数语法来用的,扣了半天,原来才发现,pg数据库中根本就没有ifnull这个函数,

    可以使用COALESCE函数代替。

    这是改正确之后的sql语句:

    SELECT tt.NAME, tt.sex, tt.idcardtype, tt.idcard, tt.mobile
        , tt.birthday, tt.ID, tt.vipid, tt.cardno, tt.cardtypename
        , tt.cardtypecode, tt.gradetypename, tt.status, tt.TYPE, tt.changecardno
        , tt.changecardnoflag, tt.PASSWORD, tt.accountmoneytype, tt.networktype, tt.usertype
        , tt.money, tt.points, tt.couponcnt, tt.relatedcnt,
        COALESCE ( tt.comname, tt.unitname )   as  unitname,
        tt.refereecode,
          tt.insuretype, tt.starteffectdate, tt.endeffectdate, tt.uniagentcode, tt.unisaleschannel
        , tt.unisalesbusitype
    FROM (
        SELECT vip.NAME, vip.sex, vip.idcardtype, vip.idcard, vip.mobile
            , vip.birthday, acc.ID, acc.vipid
            , CASE 
                WHEN acc.cardno IS NULL THEN acc.changecardno
                ELSE acc.cardno
            END AS cardno, acc.cardtypename, acc.cardtypecode, acc.gradetypename, acc.status
            , acc.TYPE, acc.changecardno, acc.changecardnoflag, acc.PASSWORD, acc.accountmoneytype
            , acc.networktype, acc.usertype, mon.money, mon.points
            , CASE 
                WHEN cp.couponcnt IS NULL THEN 0
                ELSE cp.couponcnt
            END AS couponcnt
            , (
                SELECT COUNT(0)
                FROM vip_accountrelated T
                WHERE T.vipid = vip.ID
                    AND T.accountid = acc.ID
                    AND T.dr = 0
            ) AS relatedcnt
            , (
                SELECT t1.unit_name::VARCHAR
                FROM up_org_unit t1, up_org_unit_ext t2
                WHERE t1.unit_id = t2.unit_id
                    AND t2.unit_uncode = vip.unitid
            ) AS unitname
            , (
                SELECT t1.unit_name::VARCHAR
                FROM up_org_unit t1, up_org_unit_ext t2
                WHERE t1.unit_id = t2.unit_id
                    AND t2.unit_uncode = acc.sendunitid
            ) AS comname, acc.refereecode, vip.insuretype, acc.starteffectdate, acc.endeffectdate
            , acc.uniagentcode, acc.unisaleschannel, acc.unisalesbusitype
        FROM VIP_ACCOUNT acc, VIP_INFO vip, VIP_ACCOUNTMONEY mon, (
                SELECT ac.accountid, COUNT(0) AS couponcnt
                FROM VIP_ACCOUNTCOUPON ac, VIP_COUPON cou
                WHERE ac.couponcode = cou.code
                    AND cou.status = 1
                    AND ac.dr = 0
                    AND cou.dr = 0
                GROUP BY ac.accountid
            ) cp
        WHERE acc.vipid = vip.ID
            AND acc.ID = mon.ID
            AND acc.ID = cp.accountid
            AND acc.dr = 0
            AND vip.dr = 0
            AND mon.dr = 0
    ) tt
    ORDER BY tt.usertype OFFSET ( ?- 1 ) * ? 
        LIMIT ?

    推荐一个网址:产看pgsql常用的函数:

    https://www.cnblogs.com/personblog/p/11042105.html

  • 相关阅读:
    gradient函数
    matlab函数
    二进制中1的个数
    豆瓣电影数据分析
    豆瓣电影Top250数据爬取学习
    numpy_将nan替换为均值
    多次条形图
    Gym
    Educational Codeforces Round 59 (Rated for Div. 2)
    Codeforces Round #535 (Div. 3)
  • 原文地址:https://www.cnblogs.com/dongyaotou/p/12770052.html
Copyright © 2011-2022 走看看