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  • hdu1114 Piggy-Bank

    我的代码没有通过,用了完全背包解法

    #include "iostream"
    #include "string.h"
    #include "algorithm"
    using namespace std;
    struct {
      int p,w;
    }num[1000];
    int minb(int a,int b){return a>b?b:a;}
    
    int main(){
      int Case,a,b,weight,n,i,s,m,top,min,j,k,visit[1100],f[1100],t;
      cin>>Case;
      while(Case--){
       cin>>a>>b;
       weight=b-a;
       cin>>n;
       for(i=1;i<=n;i++)cin>>num[i].p>>num[i].w;
       if(a<1||a>b){cout<<"This is impossible."<<endl;continue;}
       if(weight==0){cout<<"The minimum amount of money in the piggy-bank is 0."<<endl;continue;}
       top=n+1;
       for(i=1;i<=n;i++){
         if(num[i].w==1){
           s=1;m=weight-num[i].w;
           while(m>0){
             num[top].p=s*num[i].p;num[top].w=s*num[i].w;
             top++;
             s=2*s;
             m=m-s*num[i].w;
           }
           m=m+s*num[i].w;
           num[i].p=m/num[i].w*num[i].p;
           num[i].w=m;
         }
         else{
           s=2;m=weight-2*num[i].w;
           while(m>=0){
             num[top].p=s*num[i].p;num[top].w=s*num[i].w;
             top++;
             s=2*s;
             m=m-s*num[i].w;
           }
           m=m+s*num[i].w;
           if(m>num[i].w){
           num[top].p=m/num[i].w*num[i].p;
           num[top].w=(m/num[i].w)*num[i].w;
           top++;
           }
         }
    
       }
       //for(i=1;i<top;i++)cout<<"i.p "<<num[i].p<<" i.w "<<num[i].w<<endl;
       for(i=1;i<=weight;i++)f[i]=99999999;
       memset(visit,0,sizeof(visit));
       //for(i=1;i<=weight;i++)cout<<visit[i]<<' ';cout<<endl;
       min=99999999;visit[0]=1;
       for(i=1;i<top;i++){
         for(j=weight;j>=num[i].w;j--){
           if(visit[j-num[i].w]){
             visit[j]=1;
             f[j]=minb(f[j],f[j-num[i].w]+num[i].p);
             //cout<<j<<' '<<f[j]<<"**"<<endl;system("pause");
           }
         }
         if(visit[weight]){min=minb(min,f[weight]);visit[weight]=0;f[weight]=99999999;}
         //cout<<i<<' ';for(j=1;j<=weight;j++)cout<<f[j]<<' ';cout<<endl;
       }
    
       if(min==99999999)cout<<"This is impossible."<<endl;
       else cout<<"The minimum amount of money in the piggy-bank is "<<min<<"."<<endl;
      }
    }

    人家通过的代码,思路一对,什么都简单了,它是用了我之前有考虑到,但是没有用好,所以重新写了,重新写后,错了,嘻嘻嘻

    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #define INF 1000000000
    using namespace std;
    int dp[20000],P[1000],W[1000],E,F,N,M;
    int main(void)
    {
        int T,i,j;
        scanf("%d",&T);
        while(T--)
        {
            scanf("%d%d",&E,&F);
            M=F-E;
            scanf("%d",&N);
            for(i=0;i<N;i++)
                scanf("%d%d",&P[i],&W[i]);
            dp[0]=0;
            for(i=1;i<=M;i++)
               dp[i]=INF;
            for(i=0;i<N;i++)
               for(j=W[i];j<=M;j++)
                  dp[j]=min(dp[j-W[i]]+P[i],dp[j]);
            if(dp[M]<INF)
               printf("The minimum amount of money in the piggy-bank is %d.
    ",dp[M]);
            else
               printf("This is impossible.
    ");
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/dowson/p/3273039.html
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