[Offer收割]编程练习赛38

漏写的数字

#pragma comment(linker, "/STACK:102400000,102400000")
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<vector>
#include<algorithm>
#include<iostream>
#include<map>
#include<queue>
#include<stack>
#include<string>
#include<functional>
//#include<bits/stdc++.h>
using namespace std;
typedef long long lint;



int cmp(const void * x, const void * y) {
#define datatype int
    datatype dx = *((datatype *)(x)), dy = *((datatype *)(y));
    //x < y
    return dx > dy ? 1 : -1;
#undef datatype
}

char str[500];
int s[500];

int main() {
#ifndef ONLINE_JUDGE
    freopen("input.txt", "r", stdin);
#endif
    std::ios::sync_with_stdio(0), cin.tie(0);
    cin >> str;
    bool f, f1;
    int n = strlen(str);
    for (int i = 0; i < n; i++) s[i] = str[i] - '0';
    int ans;
    f = true, f1 = false;
    int b = s[0];
    int ptr = 1;
    while (ptr < n) {
        b++;
        if (b < 10) {
            if (s[ptr] == b) {
                ptr++;
                continue;
            } else {
                if (f1) {
                    f = false;
                    break;
                } else {
                    f1 = true;
                    ans = b;
                }
            }
        } else {
            if (s[ptr] == b / 10 && s[ptr + 1] == b % 10) {
                ptr += 2;
                continue;
            } else {
                if (f1) {
                    f = false;
                    break;
                } else {
                    f1 = true;
                    ans = b;
                }
            }
        }
    }
    if (f && f1) {
        cout << ans << endl;
        return 0;
    }
    f = true, f1 = false;
    b = s[0] * 10 + s[1];
    ptr = 2;
    while (ptr < n) {
        b++;
        if (b < 10) {
            if (s[ptr] == b) {
                ptr++;
                continue;
            } else {
                if (f1) {
                    f = false;
                    break;
                } else {
                    f1 = true;
                    ans = b;
                    ptr++;
                }
            }
        } else {
            if (s[ptr] == b / 10 && s[ptr + 1] == b % 10) {
                ptr += 2;
                continue;
            } else {
                if (f1) {
                    f = false;
                    break;
                } else {
                    f1 = true;
                    ans = b;
                }
            }
        }
    }
    if (f && f1) {
        cout << ans << endl;
        return 0;
    }
    return 0;
}

扁平化管理

#pragma comment(linker, "/STACK:102400000,102400000")
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<vector>
#include<algorithm>
#include<iostream>
#include<map>
#include<queue>
#include<stack>
#include<string>
#include<functional>
//#include<bits/stdc++.h>
using namespace std;
typedef long long lint;



int cmp(const void * x, const void * y) {
#define datatype int
    datatype dx = *((datatype *)(x)), dy = *((datatype *)(y));
    //x < y
    return dx > dy ? 1 : -1;
#undef datatype
}

lint a[100][100];
const lint inf = 0x7FFFFFFFFFFFFFFF;

int main() {
#ifndef ONLINE_JUDGE
    freopen("input.txt", "r", stdin);
#endif
    std::ios::sync_with_stdio(0), cin.tie(0);
    for (int i = 0; i < 100; i++) {
        for (int j = 1; j < 100; j++) {
            lint aaa = 1, tmp = 1;
            if (i < j - 1) continue;
            for (int k = 1; k < j; k++) {
                aaa *= (i - k + 1);
                tmp += aaa;
                if (tmp > 1e18) break;
            }
            if (tmp > 1e18) a[i][j] = inf;
            else a[i][j] = tmp;
        }
    }
    lint n, l;
    cin >> n >> l;
    bool f = false;
    for (int i = 0; i < 100; i++) {
        for (int j = 0; j < min((lint)100, l + 1); j++) {
            if (a[i][j] >= n && !f) {
                cout << i << endl;
                f = true;
            }
        }
    }
    if (!f) {
        if (l == 2) cout << n - 1 << endl;
        else if (l == 3) {
            lint tmp = (lint)sqrt(n);
            if (tmp * tmp + 1 >= n) cout << tmp << endl;
            else cout << tmp + 1 << endl;
        } else {
            for (int i = 0;; i++) {
                if (i < l - 1) continue;
                lint aaa = 1, tmp = 1;
                for (int k = 1; k < l; k++) {
                    aaa *= (i - k + 1);
                    tmp += aaa;
                    if (tmp > 1e18) break;
                }
                if (tmp > n) {
                    cout << i << endl;
                    break;
                }
            }
        }
    }
    return 0;
}

小球染色

动态规划：dp[i][j]表示决定了前i个的颜色，最后j个颜色相同的方法数。

#pragma comment(linker, "/STACK:102400000,102400000")
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<vector>
#include<algorithm>
#include<iostream>
#include<map>
#include<queue>
#include<stack>
#include<string>
#include<functional>
//#include<bits/stdc++.h>
using namespace std;
typedef long long lint;



int cmp(const void * x, const void * y) {
#define datatype int
    datatype dx = *((datatype *)(x)), dy = *((datatype *)(y));
    //x < y
    return dx > dy ? 1 : -1;
#undef datatype
}

lint dp[1005][1005];
const int mod = 1000000007;

int main() {
#ifndef ONLINE_JUDGE
    freopen("input.txt", "r", stdin);
#endif
    std::ios::sync_with_stdio(0), cin.tie(0);
    int n, m, k;
    cin >> n >> m >> k;
    memset(dp, 0, sizeof(dp));
    dp[1][1] = m;
    for (int i = 1; i <= n; i++) {
        for (int j = 1; j < k; j++) {
            dp[i + 1][j + 1] = (dp[i + 1][j + 1] + dp[i][j]) % mod;
            dp[i + 1][1] = (dp[i + 1][1] + dp[i][j] * (m - 1)) % mod;
        }
    }
    lint ans = 0;
    for (int i = 1; i < k; i++) ans = (ans + dp[n][i]) % mod;
    cout << ans << endl;
    return 0;
}

三角形面积和2