Binary Tree Zigzag Level Order Traversal 二叉树的锯齿形层序遍历
给一个二叉树的root,返回其节点值从上到下遍历,奇数层从左到右 遍历,偶数层从右到左。
Input: root = [3,9,20,null,null,15,7]
Output: [[3],[20,9],[15,7]]
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public List<List<Integer>> zigzagLevelOrder(TreeNode root) {
List<List<Integer>> ans = new ArrayList<>();
LinkedList<TreeNode> queue = new LinkedList<TreeNode>();
if(root ==null){
return ans;
}
queue.add(root);
while(!queue.isEmpty()){
List<Integer> arr = new ArrayList<>();
int length = queue.size();
for(int i =0;i<length;i++){
TreeNode n = queue.poll();
if(n.left!=null){
queue.add(n.left);
}
if(n.right!=null){
queue.add(n.right);
}
arr.add(n.val);
}
ans.add(arr);
}
int size = ans.size();
for(int i =0;i<size;i++){
if(i%2==1){
Collections.reverse(ans.get(i));
}
}
return ans;
}
}
Tag
tree
BFS