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  • MySQL中group_concat函数-和group by配合使用

    MySQL中group_concat函数
    
    完整的语法如下:
    
    group_concat([DISTINCT] 要连接的字段 [Order BY ASC/DESC 排序字段] [Separator '分隔符'])
     
    基本查询
     
    Sql代码  收藏代码
    select * from aa;  
    
    +------+------+
    | id| name |
    +------+------+
    |1 | 10|
    |1 | 20|
    |1 | 20|
    |2 | 20|
    |3 | 200 |
    |3 | 500 |
    +------+------+
    6 rows in set (0.00 sec)
     
    以id分组,把name字段的值打印在一行,逗号分隔(默认)
     
    Sql代码  收藏代码
    select id,group_concat(name) from aa group by id;  
    
    +------+--------------------+
    | id| group_concat(name) |
    +------+--------------------+
    |1 | 10,20,20|
    |2 | 20 |
    |3 | 200,500|
    +------+--------------------+
    3 rows in set (0.00 sec)
     
    以id分组,把name字段的值打印在一行,分号分隔
     
    Java代码  收藏代码
    select id,group_concat(name separator ';') from aa group by id;  
    
    +------+----------------------------------+
    | id| group_concat(name separator ';') |
    +------+----------------------------------+
    |1 | 10;20;20 |
    |2 | 20|
    |3 | 200;500 |
    +------+----------------------------------+
    3 rows in set (0.00 sec)
     
    以id分组,把去冗余的name字段的值打印在一行,
    
    逗号分隔
     
    Sql代码  收藏代码
    select id,group_concat(distinct name) from aa group by id;  
    
    +------+-----------------------------+
    | id| group_concat(distinct name) |
    +------+-----------------------------+
    |1 | 10,20|
    |2 | 20 |
    |3 | 200,500 |
    +------+-----------------------------+
    3 rows in set (0.00 sec)
     
    以id分组,把name字段的值打印在一行,逗号分隔,以name排倒序
     
    Sql代码  收藏代码
    select id,group_concat(name order by name desc) from aa group by id;  
    
    +------+---------------------------------------+
    | id| group_concat(name order by name desc) |
    +------+---------------------------------------+
    |1 | 20,20,10 |
    |2 | 20|
    |3 | 500,200|
    +------+---------------------------------------+
    3 rows in set (0.00 sec)
     
    测试sql,项目中用到的。
    Sql代码  收藏代码
    SELECT  
            EMPLOYEES.EMPID  
            ,EMPLOYEES.EMPNAME  
            ,DEPARTMENTS.DEPARTMENTNAME  
            ,EMPLOYEES.DEPTID  
            ,EMPLOYEES.EMPPWD  
            ,EMPLOYEES.INSIDEEMAIL  
            ,EMPLOYEES.OUTSIDEEMAIL  
            ,EMPLOYEES.DELEFLAG  
            ,EMPLOYEES.EMPCLASS  
            ,(CONCAT('[', <span style="color: #ff0000;">GROUP_CONCAT</span>  
    (ROLE.Role_Name SEPARATOR '],['), ']')) AS ROLENAME  
            ,(concat( '[', (  
                SELECT  
                        <span style="color: #ff0000;">GROUP_CONCAT</span>  
    (DEPARTMENTS.DEPARTMENTNAME separator '],[')  
                    FROM  
                        EMP_ROLE_DEPT  
                            LEFT JOIN DEPARTMENTS  
                                ON (  
                                    DEPARTMENTS.DEPARTMENTID = EMP_ROLE_DEPT.DEPTID  
                                    AND DEPARTMENTS.DELEFLAG = 0  
                                )  
                    GROUP BY  
                        EMP_ROLE_DEPT.EMPID  
                    HAVING  
                        EMP_ROLE_DEPT.EMPID = EMPLOYEES.EMPID  
            ),']')) AS DEPARTMENTRIGHT  
        FROM  
            EMPLOYEES  
                LEFT JOIN DEPARTMENTS  
                    ON (  
                        DEPARTMENTS.DEPARTMENTID = EMPLOYEES.DEPTID  
                        AND DEPARTMENTS.DELEFLAG = 0  
                    )  
                LEFT JOIN ROLE_EMP  
                    ON (ROLE_EMP.EMP_ID = EMPLOYEES.EMPID)  
                LEFT JOIN ROLE  
                    ON (ROLE_EMP.ROLE_ID = ROLE.ROLE_ID)  
    <span style="color: #ff0000;">    GROUP BY  
            EMPLOYEES.EMPID</span>  
      
        HAVING  
            EMPLOYEES.EMPID LIKE '%%'  
            AND EMPLOYEES.EMPNAME LIKE '%%'  
            AND EMPLOYEES.DELEFLAG = 0  
            AND (  
                EMPLOYEES.EMPCLASS = '1'  
                OR EMPLOYEES.EMPCLASS = '2'  
            )  
            AND EMPLOYEES.DEPTID = '001' LIMIT 0  
            ,16   
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  • 原文地址:https://www.cnblogs.com/dreamzhiya/p/4727456.html
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