1001 A+B Format (20分)

Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:

Each input file contains one test case. Each case contains a pair of integers a and b where −. The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

 

Sample Output:

-999,991

大意：

计算 +  并以标准格式输出总和-也就是说，必须用逗号将数字分成三组（除非少于四位）。

输入规格：

每个输入文件包含一个测试用例。每个案例包含一对整数一种 和 b 哪里 −。这些数字用空格分隔。

输出规格：

对于每个测试用例，您应该输出 一种 和 b在一排。总和必须以标准格式书写。

输入样例：

-1000000 9

 

样本输出：

-999,991

#include<iostream>
#include<algorithm>
#include<cstdlib>
#include<cstdio>
#include<queue>
#include<stack>
#include<cstring>
#include<string.h>
#include<cmath>
using namespace std;
const int maxn=1010;
    

int main(){
    int a,b;
    scanf("%d %d",&a,&b);
    int c=a+b;
    c=abs(c);
    int d[maxn];
    int i=0;
    while(c){
        d[i]=c%10;
        c/=10; 
        i++;
    }
    if(a+b<0){
        printf("-");
    }
    if(a+b==0){
        printf("0
");
        return 0;
    }
    for(int j=i-1;j>=0;j--){
        printf("%d",d[j]);
        if((j)%3==0&&j>0){
            printf(",");
        }
        
        
    }
    printf("
"); 
    
    return 0;
}