1005 Spell It Right (20分)

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (≤).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

12345

Sample Output:

one five
题意：求数字N中各位数字的和，并用英文输出

#include<iostream>
#include<algorithm>
#include<cstdio>
#include<cstring>
#include<string.h>
#include<cstdlib>
using namespace std;
const int maxn=10010;
void change(int a[],int i){
        if(a[i]==0){
            cout<<"zero";
        }
        else if(a[i]==1){
            cout<<"one";
        }
        else if(a[i]==2){
            cout<<"two";
        }
        else if(a[i]==3){
            cout<<"three";
        }
        else if(a[i]==4){
            cout<<"four";
        }
        else if(a[i]==5){
            cout<<"five";
        }
        else if(a[i]==6){
            cout<<"six";
        }
        else if(a[i]==7){
            cout<<"seven";
        }
        else if(a[i]==8){
            cout<<"eight";
        }
        else if(a[i]==9){
            cout<<"nine";
        }
}
int main(){
    string N;
    cin>>N;
    long leng=N.length();
    long sum=0;
    for(int i=0;i<leng;i++){
        sum+=N[i]-'0';
    }
//    cout<<sum<<endl;
    long s=sum;
    if(s==0){    //单独考虑为零的情况
        cout<<"zero"<<endl;
        return 0;
    }
    int a[maxn];
    int i=0;
    while(s!=0){
        a[i]=s%10;
        s/=10;
        i++;
    }
    for(int j=i-1;j>=0;j--){
        change(a,j);
        if(j>0){
            cout<<" ";
        }
        else{
            cout<<endl;
        }
    }
    
    return 0;
}