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  • 1065 A+B and C (64bit) (20 分)

    Given three integers A, B and C in [−], you are supposed to tell whether A+B>C.

    Input Specification:

    The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

    Output Specification:

    For each test case, output in one line Case #X: true if A+B>C, or Case #X: false otherwise, where X is the case number (starting from 1).

    Sample Input:

    3
    1 2 3
    2 3 4
    9223372036854775807 -9223372036854775808 0
     

    Sample Output:

    Case #1: false
    Case #2: true
    Case #3: false
     

    Thanks to Jiwen Lin for amending the test data.

     思路:根据a,b,sum的正负判断是否溢出。注意:用cin输入会造成最后一个测试点过不去!!!,换成scanf输入
     
    #include<bits/stdc++.h>
    using namespace std;
    const int maxn=1000010;
    
    int main(){
        int n;
        long long a,b,c;
        long long sum=0;
        scanf("%lld",&n);
        for(int i=0;i<n;i++){
            sum=0;
            scanf("%lld %lld %lld",&a,&b,&c);
            sum=a+b;
            if(a>0&&b>0&&sum<0){
                printf("Case #%d: true
    ",i+1);
            }
            else if(a<0&&b<0&&sum>=0){
                printf("Case #%d: false
    ",i+1);
            }
            else if(sum>c){
                printf("Case #%d: true
    ",i+1);
            }
            else{
                printf("Case #%d: false
    ",i+1);
            }
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/dreamzj/p/14932912.html
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