1077 Kuchiguse (20 分)

The Japanese language is notorious for its sentence ending particles. Personal preference of such particles can be considered as a reflection of the speaker's personality. Such a preference is called "Kuchiguse" and is often exaggerated artistically in Anime and Manga. For example, the artificial sentence ending particle "nyan~" is often used as a stereotype for characters with a cat-like personality:

• Itai nyan~ (It hurts, nyan~)

• Ninjin wa iyada nyan~ (I hate carrots, nyan~)

Now given a few lines spoken by the same character, can you find her Kuchiguse?

Input Specification:

Each input file contains one test case. For each case, the first line is an integer N (2). Following are N file lines of 0~256 (inclusive) characters in length, each representing a character's spoken line. The spoken lines are case sensitive.

Output Specification:

For each test case, print in one line the kuchiguse of the character, i.e., the longest common suffix of all N lines. If there is no such suffix, write nai.

Sample Input 1:

3
Itai nyan~
Ninjin wa iyadanyan~
uhhh nyan~

 

Sample Output 1:

nyan~

 

Sample Input 2:

3
Itai!
Ninjinnwaiyada T_T
T_T

 

Sample Output 2:

nai

 

 题解：反转所有字符串，比较2-n字符串是否与第一个字符串字符相同，设立计数器统计相同前缀长度

#include<bits/stdc++.h>
using namespace std;
const int maxn=1010;
#define inf 0x3fffffff
int main(){
    int n;
    cin>>n;
    getchar();
    string st[maxn];
    int minLen=inf;
    for(int i=0;i<n;i++){
        getline(cin,st[i]);
        reverse(st[i].begin(),st[i].end());
        if(st[i].length()<minLen){
            minLen=st[i].length();
        }
    }
    int cnt=0;
    for(int i=0;i<minLen;i++){
        char c=st[0][i];
        bool same=true;
        for(int j=1;j<n;j++){
            if(st[j][i]!=c){
                same=false;
            }
        }
        if(same){
            cnt++;
        }
        else{
            break;
        }
    }
    if(cnt==0){
        cout<<"nai"<<endl;
        return 0;
    }
    string s=st[0].substr(0,cnt);
    reverse(s.begin(),s.end());
    for(int i=0;i<cnt;i++){
        cout<<s[i];
    }
    cout<<endl;
    return 0;
}