hdu 2053 Switch Game

Problem Description

There are many lamps in a line. All of them are off at first. A series of operations are carried out on these lamps. On the i-th operation, the lamps whose numbers are the multiple of i change the condition ( on to off and off to on ).

 

Input

Each test case contains only a number n ( 0< n<= 10^5) in a line.

 

Output

Output the condition of the n-th lamp after infinity operations ( 0 - off, 1 - on ).

 

Sample Input

1

5

 

Sample Output

1

0

Hint

hint

Consider the second test case:

The initial condition :0 0 0 0 0 …

After the first operation : 1 1 1 1 1 …

After the second operation : 1 0 1 0 1 …

After the third operation : 1 0 0 0 1 …

After the fourth operation : 1 0 0 1 1 …

After the fifth operation : 1 0 0 1 0 …

The later operations cannot change the condition of the fifth lamp any more. So the answer is 0.

这题是水题，找出n的约数的个数count，若为偶数则是0，若为奇数则为1；代码如下：

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
    int n,i,count;
    while(scanf("%d",&n)!=EOF)
    {
        count=0;
        for(i=1;i<=sqrt(n);i++)//求n的约数的个数
        {
            if(n%i==0)
            {
                count+=2;
                if(i==n/i)
                    count--;
            }
        }
        if(count%2==0) printf("0
");
        else printf("1
");
    }
    return 0;
}