zoukankan      html  css  js  c++  java
  • grouping sets,cube,rollup,grouping__id,group by

    例1:

    hive -e"

    select

        type

        ,status

        ,count(1)

    from

        usr_info

    where pt='2015-09-14'

    group by type,status

    grouping sets ((type,status),( type),());

    ">one.txt

    Grouping sets按照各种指定聚类汇总方式,如group by type,status grouping sets ((type,status),( type),())

    表示group by type,status union all  group by type union all group by ()

    得到

    type status       _c2

    NULL         NULL         69467

    1       NULL         68216

    1       1       63615

    1       2       540

    1       4       4061

    2       NULL         891

    2       1       873

    2       2       18

    3       NULL         360

    3       1       340

    3       4       20

    例2:

    hive -e"

    select

        type

        ,status

        ,count(1)

    from

        usr_info

    where pt='2015-09-14'

    group by type,status with rollup;

    ">two.txt

    group by type,status with rollup按照以type为主的固定聚类汇总方式,如同group by type,status grouping sets ((type,status),( type),()) ,不过形式已经固定了,表示group by type,status union all  group by type union all group by ()

    得到

    Type status      _c2

    NULL         NULL         69467

    1       NULL         68216

    1       1       63615

    1       2       540

    1       4       4061

    2       NULL         891

    2       1       873

    2       2       18

    3       NULL         360

    3       1       340

    3       4       20

    例3:

    hive -e"

    select

        type

        ,status

        ,count(1)

    from

        usr_info

    where pt='2015-09-14'

    group by type,status with cube;

    ">three.txt

    group by type,status with cube按照以type和status为主的固定聚类汇总方式,如同group by type,status grouping sets ((type,status),( type),(status),()) ,不过形式已经固定了,表示group by type,status union all group by type union all group by status union all group by ()

    得到

    Type status      _c2

    NULL         NULL         69467

    NULL         1       64828

    NULL         2       558

    NULL         4       4081

    1       NULL         68216

    1       1       63615

    1       2       540

    1       4       4061

    2       NULL         891

    2       1       873

    2       2       18

    3       NULL         360

    3       1       340

    3       4       20

    例4:

    hive -e"

    select

        type

        ,status

        ,grouping__id

        ,count(1)

    from

        usr_info

    where pt='2015-09-14'

    group by type,status with cube;

    ">five.txt

    type

        ,status

        ,grouping__id

    grouping__id(两条横线)函数判断其参数是否参与了分组,如果参与则返回1,如果没有参与了分组则返回0

    而其多个参数的形式则将其每个参数进行grouping__id运算后返回的值拼成二进制后转换为十进制返回,

    grouping_id(argn,...,arg2,arg1)=grouping_id(argn)*2^(n-1)+...+grouping_id(arg2)*2^1+grouping_id(arg1)*2^0('^'表示幂运算)。

    Hive中grouping__id不带参数,用法见例子。

    得到

    type status    grouping__id   _c3

    NULL         NULL         0       69467

    NULL         1       2       64828

    NULL         2       2       558

    NULL         4       2       4081

    1       NULL         1       68216

    1       1       3       63615

    1       2       3       540

    1       4       3       4061

    2       NULL         1       891

    2       1       3       873

    2       2       3       18

    3       NULL         1       360

    3       1       3       340

    3       4       3       20

  • 相关阅读:
    ping和telnet
    nginx下No input file specified错误的解决
    【Git】删除某个全局配置项
    windows7使用Sphinx+PHP+MySQL详细介绍
    TortoiseGit需要重复填写用户名和密码的问题
    【算法】字符串数组的排序时间复杂度问题
    java随机生成6位随机数 5位随机数 4位随机数
    Linux下MySQL报Table 'xxx' doesn't exist错误解决方法,表名存在大小写区分
    Cannot find ./catalina.sh The file is absent or does not have execute permission This file is nee
    Linux 服务器安装jdk,mysql,tomcat简要教程
  • 原文地址:https://www.cnblogs.com/dudumiaomiao/p/4813149.html
Copyright © 2011-2022 走看看