c# jobject 的数据结构的解析

首先下载Newtonsoft.Json，增加引用using Newtonsoft.Json.Linq;

把jobject的内容提取出来，Jobject的内容格式如下:

 

{
 "code": 200,
 "msg": "SUCCESS",
 "data": {
  "id": "12345678",
  "name": "张三",
  "sex": "男",
  "result": {
   "access_token": "49d58eacd7811e463429a1ae10b42173",
   "user_info": [{
    "school": "社会大学",
    "major": "软件开发",
    "education": "本科",
    "score": 97
   }, {
    "school": "湖南大学",
    "major": "软件工程",
    "education": "研究生",
    "score": 100
   }]
  }
 }
}

可放到json官网在线JSON校验格式化工具里解析。

 

代码如下：                   

1，新建类：
        public class UserInfo
        {
            public string id { get; set; }
            public string name { get; set; }
            public string sex { get; set; }
            public string access_token { get; set; }
            public string school { get; set; }
            public string major { get; set; }
            public string education { get; set; }
            public string score { get; set; }
        }

2，获取值：

            JObject result = new JObject();//假设result为数据结构
            UserInfo userinfo = new UserInfo();
            userinfo.id = result["data"].Value<string>("id");//id
            userinfo.name = result["data"].Value<string>("name"); //name
            userinfo.sex = result["data"].Value<string>("sex"); //sex
            userinfo.access_token= result["data"]["result"]["access_token"].ToString();//access_token
            JArray res = result["data"]["result"].Value<JArray>("user_info");
            JObject obj = JObject.Parse(res[0].ToString());//只获取数据结构中第一个userinfo里的数据信息
            userinfo.school = obj.Value<string>("school"); //schoool
            userinfo.major = obj.Value<string>("major");//major
            userinfo.education = obj.Value<string>("education");//education
            userinfo.score= obj.Value<string>("score");//score