zoukankan      html  css  js  c++  java
  • CF487E Tourists——圆方树

    既然有这条性质,这题就很简单了:
    (可能在a->b的简单路径上的点集,就是圆方树上a->b路径上方点代表的点双的并集)
    对每一个方点维护一个(multiset),代表其在圆方树上子结点的最小值,这样更改就只需要改父结点辣。剩下的用树剖乱搞就行了

    #include <bits/stdc++.h>
    
    using namespace std;
    
    #define N 200000
    #define INF 0x3f3f3f3f
    #define lson (o<<1)
    #define rson (o<<1|1)
    #define mid ((l+r)>>1)
    
    int n, m, q, tot;
    int w[N+5], dfn_clk, dfn[N+5], low[N+5], id[N+5];
    int stk[N+5], tp;
    int sz[N+5], fa[N+5], hson[N+5], rt[N+5], top[N+5], d[N+5];
    vector<int> G[N+5], T[N+5];
    int minv[4*N+5];
    multiset<int> s[N+5];
    
    void tarjan(int u) {
        low[u] = dfn[u] = ++dfn_clk;
        stk[++tp] = u;
        for(int i = 0; i < G[u].size(); ++i) {
            int v = G[u][i];
            if(!dfn[v]) {
                tarjan(v);
                low[u] = min(low[u], low[v]);
                if(low[v] == dfn[u]) {
                    ++tot;
                    for(int x = 0; x != v; --tp) {
                        x = stk[tp];
                        T[tot].push_back(x);
                        T[x].push_back(tot);
                    }
                    T[tot].push_back(u);
                    T[u].push_back(tot);
                }
                
            }
            else low[u] = min(low[u], dfn[v]);
        }
    }
    
    int minval(int u) {
        if(s[u].size()) return *s[u].begin();
        else return INF;
    }
    
    void dfs1(int u, int pa) {
        fa[u] = pa;
        sz[u] = 1;
        d[u] = d[pa]+1;
        for(int i = 0; i < T[u].size(); ++i) {
            int v = T[u][i];
            if(v == pa) continue;
            if(u > n) s[u].insert(w[v]);
            dfs1(v, u);
            if(sz[v] > sz[hson[u]]) hson[u] = v;
            sz[u] += sz[v];
        }
    }
    
    void dfs2(int u, int tp) {
        dfn[u] = ++dfn_clk, id[dfn_clk] = u;
        top[u] = tp;
        if(hson[u]) dfs2(hson[u], tp);
        for(int i = 0; i < T[u].size(); ++i) {
            int v = T[u][i];
            if(v == fa[u] || v == hson[u]) continue;
            dfs2(v, v);
        }
        rt[u] = dfn_clk;
    }
    
    int lca(int x, int y) {
        while(top[x] != top[y]) d[top[x]] > d[top[y]] ? x = fa[top[x]] : y = fa[top[y]];
        return d[x] < d[y] ? x : y;
    }
    
    void pushup(int o) {
        minv[o] = min(minv[lson], minv[rson]);
    }
    
    void build(int o, int l, int r) {
        if(l == r) {
            minv[o] = id[l] > n ? minval(id[l]) : INF;
            return ;
        }
        build(lson, l, mid), build(rson, mid+1, r);
        pushup(o);
    }
    
    void modify(int o, int l, int r, int x, int k) {
        if(l == r) {
            minv[o] = k;
            return ;
        }
        if(x <= mid) modify(lson, l, mid, x, k);
        else modify(rson, mid+1, r, x, k);
        pushup(o);
    }
    
    int queryMin(int o, int l, int r, int L, int R) {
        if(L <= l && r <= R) return minv[o];
        int ret = INF;
        if(L <= mid) ret = min(ret, queryMin(lson, l, mid, L, R));
        if(R > mid) ret = min(ret, queryMin(rson, mid+1, r, L, R));
        return ret;
    }
    
    int query(int x, int y) {
        int z = lca(x, y), ret = INF;
        while(top[x] != top[z]) ret = min(ret, queryMin(1, 1, tot, dfn[top[x]], dfn[x])), x = fa[top[x]];
        ret = min(ret, queryMin(1, 1, tot, dfn[z], dfn[x]));
        while(top[y] != top[z]) ret = min(ret, queryMin(1, 1, tot, dfn[top[y]], dfn[y])), y = fa[top[y]];
        ret = min(ret, queryMin(1, 1, tot, dfn[z], dfn[y]));
        if(z > n) ret = min(ret, w[fa[z]]);
        else ret = min(ret, w[z]);
        return ret;
    }
    
    int main() {
        scanf("%d%d%d", &n, &m, &q);
        tot = n;
        for(int i = 1; i <= n; ++i) scanf("%d", &w[i]);
        for(int i = 1, x, y; i <= m; ++i) {
            scanf("%d%d", &x, &y);
            G[x].push_back(y), G[y].push_back(x);
        }
        tarjan(1);
        dfn_clk = 0;
        dfs1(1, 0), dfs2(1, 1);
        build(1, 1, tot);
        char type[2];
        for(int i = 1, x, y; i <= q; ++i) {
            scanf("%s%d%d", type, &x, &y);
            if(type[0] == 'C') {
                if(x != 1) {
                    int t = minval(fa[x]);
                    s[fa[x]].erase(s[fa[x]].lower_bound(w[x]));
                    s[fa[x]].insert(y);
                    if(minval(fa[x]) != t) modify(1, 1, tot, dfn[fa[x]], minval(fa[x]));
                }
                w[x] = y;
            }
            else {
                printf("%d
    ", query(x, y));
            }
        }
        return 0;
    }
    
  • 相关阅读:
    使用IOCP完成端口队列做任务队列
    对Zlib单元进行再封装
    XmlReader/XmlWriter 类
    TextReader/TextWriter 的类
    LINQ to XML
    Xml序列化
    动态Linq(结合反射)
    设计模式总结
    深入了解.Net上下文
    应用程序域
  • 原文地址:https://www.cnblogs.com/dummyummy/p/10744238.html
Copyright © 2011-2022 走看看