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  • java初级问题

    1.纯随机数发生器

    public class suijishu
    {
            private static final int N = 200;
            private static final int LEFT = 40;
            private static final int RIGHT = 1000;
            private static long x0 = 1L;
            private long a = 1103515245L;
            private long c = 12345L;
            private long m = 2147483648L;
                private long rand ( long r )
                {
                  r = ( r * a + c ) % m;                                              
              return r;
            }
            private long little ( int a, int b, long rand )
            {
              return a + rand % ( b - a + 1 );
            }
            private void recursion ( int count, long rand )    
            {
             if (count >= N)
             {return;}
             rand = rand (rand);
             long r = little (LEFT, RIGHT, rand);
             System.out.println (r);
             recursion (++count, rand);
            }
            public static void main ( String[] args )
            {
            suijishu recur = new suijishu ();
             recur.recursion (0, x0);
            }
    }

    2.当函数的形参类型不同时,函数可以重载。

    3.组合数计算

    import java.util.Scanner;
    public class zuheshu1 {
        public static int jiecheng(int x){
            int m=1;
        if(x<0) {
            System.out.println("输入错误");
            System.exit(0);
        }
        else if(x==0||x==1)
            m=1;
        else 
            m=jiecheng(x-1)*x;
        return m;
        }
        public static int jszhs1(int k,int n){
        int c=jiecheng(n)/(jiecheng(k)*jiecheng(n-k));
        return c;
        }
        public static int jszhs2(int n,int k) {
        int i=1;
           int c=1;
        for(i=k;k<n;i++) {
            c=c*(i/(i+k))*jszhs1(k,i-1);
        }
        return c;
        }
        public static int jszhs3(int k,int n) {
            int c=1;
            if(k==n) {return c;}
            else {return (n/(n-k))*jszhs3(k,n-1);}
        }
        public static void main(String args[]) {
            System.out.print("请选择组合数运算方法:1组合数公式;2递推杨辉三角;3递归");
            Scanner sc=new Scanner(System.in);
            int d=sc.nextInt();
            System.out.print("请输入组合数中的k和n:");
            int a=sc.nextInt();
            int b=sc.nextInt();
            switch(d) {
            case 1:System.out.println("结果为:"+jszhs1(a,b));break;
            case 2:System.out.println("结果为:"+jszhs2(a,b));break;
            case 3:System.out.println("结果为:"+jszhs3(a,b));break;
            }
        }
    }

    4.汉诺塔问题

    import java.util.Scanner;
    public class hannuota {
        public static void yidong(int panzi,int kaishi,int zhongjian,int zuihou) {
            if(panzi==1) {
                System.out.println(kaishi+"-->"+zhongjian);
                return;
            }
            yidong(panzi-1,kaishi,zuihou,zhongjian);    
            System.out.println(kaishi+"-->"+zhongjian);
            yidong(panzi-1,zuihou,zhongjian,kaishi);
        
        }
        public static void main(String args[]) {
            System.out.println("请输入盘子数:");
            Scanner sc=new Scanner(System.in);
            int n=sc.nextInt();
            System.out.println("移动方法为:");
            yidong(n,1,3,2);
        }
    
    }

    5.回文字符串

    import java.util.Scanner;
    class huiwen {
        public static int panduan(String s) {
            int length=s.length();
            if(length==0||length==1)
                return 1;
            char first=s.charAt(0);
            char last=s.charAt(length-1);
            if(first!=last)
                return 0;
            return panduan(s.substring(1, length-1));
        }
        public static void main(String args[]) {
            Scanner sc=new Scanner(System.in);
            System.out.println("请输入一个字符串:");
            String s=sc.nextLine();
            if(panduan(s)==1) System.out.println("是回文字符串");
            else System.out.println("不是回文字符串");
        }
    
    }
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  • 原文地址:https://www.cnblogs.com/duowenjia/p/7664285.html
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