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^_^
*SQLDB中图片的读取*
使用asp.net将图片上传并存入SqlServer中,然后从SqlServer中读取并显示出来
在UpPhoto.aspx文件中添加如下:
<input id="UpPhoto" name="UpPhoto" runat="server" type="file">
<asp:Button id="btnAdd" name="btnAdd" runat="server" Text="上传"></asp:Button>
然后在后置代码文件UpPhoto.aspx.cs添加btnAdd按钮的单击事件处理代码:
private void btnAdd_Click(object sender, System.EventArgs e)
{
//获得图象并把图象转换为byte[]
HttpPostedFile upPhoto=UpPhoto.PostedFile;
int upPhotoLength=upPhoto.ContentLength;
byte[] PhotoArray=new Byte[upPhotoLength];
Stream PhotoStream=upPhoto.InputStream;
PhotoStream.Read(PhotoArray,0,upPhotoLength);
//连接数据库
SqlConnection conn=new SqlConnection();
conn.ConnectionString="Data Source=localhost;Database=test;User Id=sa;Pwd=sa";
SqlCommand cmd=new SqlCommand("UpdateImage",conn);
cmd.CommandType=CommandType.StoredProcedure;
cmd.Parameters.Add("@UpdateImage",SqlDbType.Image);
cmd.Parameters["@UpdateImage"].Value=PhotoArray;
//如果你希望不使用存储过程来添加图片把上面四句代码改为:
//string strSql="Insert into test(FImage) values(@FImage)";
//SqlCommand cmd=new SqlCommand(strSql,conn);
//cmd.Parameters.Add("@FImage",SqlDbType.Image);
//cmd.Parameters["@FImage"].Value=PhotoArray;
conn.Open();
cmd.ExecuteNonQuery();
conn.Close();
}
二,从SqlServer中读取并显示出来
在需要显示图片的地方添加如下代码:
<asp:image id="imgPhoto" runat="server" ImageUrl="ShowPhoto.aspx"></asp:image>
ShowPhoto.aspx主体代码:
private void Page_Load(object sender, System.EventArgs e)
{
if(!Page.IsPostBack)
{
SqlConnection conn=new SqlConnection();
conn.ConnectionString="server=localhost; database=test; uid=sa; pwd=";
string strSql="select * from test where id=1";//这里假设获取id为1的图片
SqlCommand cmd=new SqlCommand(strSql,conn);
conn.Open();
SqlDataReader reader=cmd.ExecuteReader();
if(reader.Read())
{
Response.ContentType=reader["FImage"].ToString();
//Response.BinaryWrite((Byte[])reader["FImage"]);
Response.End();
}
reader.Close();
conn.Close();
}
}
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