题意:给定一个n*m的矩阵,问你里面有几面积为奇数的正方形。
析:首先能知道的是,大的矩阵是包括小的矩阵的,而且面积为奇数,我们只要考虑恰好在边界上的正方形即可,画几个看看就知道了,如果是3*3的有3个,
5*5有5个,偶数没有,因为面积为奇数。那么结果就有了。
代码如下:
#pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream> #include <cstring> #include <set> #include <queue> #include <algorithm> #include <vector> #include <map> #include <cctype> #include <cmath> #include <stack> #include <sstream> #define frer freopen("in.txt", "r", stdin) #define frew freopen("out.txt", "w", stdout) using namespace std; typedef long long LL; typedef unsigned long long ULL; typedef pair<int, int> P; const int INF = 0x3f3f3f3f; const double inf = 0x3f3f3f3f3f3f; const double PI = acos(-1.0); const double eps = 1e-8; const int maxn = 5e5 + 5; const int mod = 1e9 + 7; const char *mark = "+-*"; const int dr[] = {1, 0, -1, 0}; const int dc[] = {0, 1, 0, -1}; const char *de[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"}; int n, m; const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; inline int Min(int a, int b){ return a < b ? a : b; } inline int Max(int a, int b){ return a > b ? a : b; } inline LL Min(LL a, LL b){ return a < b ? a : b; } inline LL Max(LL a, LL b){ return a > b ? a : b; } inline bool is_in(int r, int c){ return r >= 0 && r < n && c >= 0 && c < m; } int main(){ while(scanf("%d %d", &n, &m) && n){ LL ans = 0; int t = Min(n, m); for(int i = 3; i <= t; i += 2) ans += (LL)i * (LL)(n+1-i) * (LL)(m+1-i); ans += (LL)n * (LL)m; cout << ans << endl; } return 0; }