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  • CodeForces 709A Juicer (水题, 模拟)

    题意:给定 n 个桔子的大小,一个杯子的容积,一个最大限度,挨着挤桔子汁,如果大小大于限度,扔掉,如果不杯子满了倒掉,问你要倒掉多少杯。

    析:直接按要求模拟就好,满了就清空杯子。

    代码如下:

    #pragma comment(linker, "/STACK:1024000000,1024000000")
    #include <cstdio>
    #include <string>
    #include <cstdlib>
    #include <cmath>
    #include <iostream>
    #include <cstring>
    #include <set>
    #include <queue>
    #include <algorithm>
    #include <vector>
    #include <map>
    #include <cctype>
    #include <cmath>
    #include <stack>
    #define freopenr freopen("in.txt", "r", stdin)
    #define freopenw freopen("out.txt", "w", stdout)
    using namespace std;
    
    typedef long long LL;
    typedef pair<int, int> P;
    const int INF = 0x3f3f3f3f;
    const double inf = 0x3f3f3f3f3f3f;
    const double PI = acos(-1.0);
    const double eps = 1e-8;
    const int maxn = 1e5 + 5;
    const int mod = 1e8;
    const char *mark = "+-*";
    const int dr[] = {-1, 0, 1, 0, 1, 1, -1, -1};
    const int dc[] = {0, 1, 0, -1, -1, 1, 1, -1};
    int n, m;
    const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    inline int Min(int a, int b){ return a < b ? a : b; }
    inline int Max(int a, int b){ return a > b ? a : b; }
    inline LL Min(LL a, LL b){ return a < b ? a : b; }
    inline LL Max(LL a, LL b){ return a > b ? a : b; }
    inline bool is_in(int r, int c){
        return r >= 0 && r < n && c >= 0 && c < m;
    }
    
    int main(){
        LL b, d;
        cin >> n >> b >> d;
        LL x, sum = 0;
        int ans = 0;
        for(int i = 0; i < n; ++i){
            cin >> x;
            if(x > b)   continue;
            sum += x;
            if(sum > d)  sum = 0, ++ans;
        }
        cout << ans << endl;
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/dwtfukgv/p/5808809.html
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