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  • UVaLive 6581 && Gym 100299B What does the fox say? (模拟+STL)

    题意:给定一些动物的叫声,然后再定某些动物的叫声,让你去除这些叫声后得到的叫声。

    析:先存储所有的叫声,然后用map来记录其他的叫声,在输出时再判定一下就好。

    代码如下:

    #pragma comment(linker, "/STACK:1024000000,1024000000")
    #include <cstdio>
    #include <string>
    #include <cstdlib>
    #include <cmath>
    #include <iostream>
    #include <cstring>
    #include <set>
    #include <queue>
    #include <algorithm>
    #include <vector>
    #include <map>
    #include <cctype>
    #include <cmath>
    #include <stack>
    #include <sstream>
    #define freopenr freopen("in.txt", "r", stdin)
    #define freopenw freopen("out.txt", "w", stdout)
    using namespace std;
    
    typedef long long LL;
    typedef pair<int, int> P;
    const int INF = 0x3f3f3f3f;
    const double inf = 0x3f3f3f3f3f3f;
    const double PI = acos(-1.0);
    const double eps = 1e-8;
    const int maxn = 1e5 + 5;
    const int mod = 1e9 + 7;
    const int dr[] = {-1, 0, 1, 0};
    const int dc[] = {0, 1, 0, -1};
    const char *de[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};
    int n, m;
    const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    inline int Min(int a, int b){ return a < b ? a : b; }
    inline int Max(int a, int b){ return a > b ? a : b; }
    inline LL Min(LL a, LL b){ return a < b ? a : b; }
    inline LL Max(LL a, LL b){ return a > b ? a : b; }
    inline bool is_in(int r, int c){
        return r >= 0 && r < n && c >= 0 && c < m;
    }
    vector<string> ans;
    map<string, int> mp;
    
    int main(){
        int T;  cin >> T;
        getchar();
        while(T--){
            ans.clear();
            mp.clear();
            string s;
            getline(cin, s);
            stringstream ss(s);
            while(ss >> s)  ans.push_back(s);
            while(getline(cin, s) && s != "what does the fox say?"){
                stringstream ss(s);
                for(int i = 0; ss >> s; ++i)
                    if(i > 1)  mp[s] = 1;
            }
            bool ok = false;
            for(int i = 0; i < ans.size(); ++i){
                if(!mp[ans[i]]){
                    if(ok)  putchar(' ');
                    printf("%s", ans[i].c_str());
                    ok = true;
                }
            }
            printf("
    ");
        }
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/dwtfukgv/p/5898177.html
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