zoukankan      html  css  js  c++  java
  • URAL 2021 Scarily interesting! (贪心+题意)

    题意:给定两个队伍的每个人的得分,让你安排怎么比赛才能使得观众知道冠军的时间最长。

    析:贪心,很简单,就是先开始总分高的先出最差劲的,总分低的先出最厉害的,这个题当时实在是读的不明白啊,WA了好多次。

    代码如下:

    #pragma comment(linker, "/STACK:1024000000,1024000000")
    #include <cstdio>
    #include <string>
    #include <cstdlib>
    #include <cmath>
    #include <iostream>
    #include <cstring>
    #include <set>
    #include <queue>
    #include <algorithm>
    #include <vector>
    #include <map>
    #include <cctype>
    #include <cmath>
    #include <stack>
    #include <sstream>
    #define debug() puts("++++");
    #define gcd(a, b) __gcd(a, b)
    #define lson l,m,rt<<1
    #define rson m+1,r,rt<<1|1
    #define freopenr freopen("in.txt", "r", stdin)
    #define freopenw freopen("out.txt", "w", stdout)
    using namespace std;
    
    typedef long long LL;
    typedef unsigned long long ULL;
    typedef pair<int, int> P;
    const int INF = 0x3f3f3f3f;
    const LL LNF = 1e16;
    const double inf = 0x3f3f3f3f3f3f;
    const double PI = acos(-1.0);
    const double eps = 1e-8;
    const int maxn = 1e5 + 10;
    const int mod = 1e9 + 7;
    const int dr[] = {-1, 0, 1, 0};
    const int dc[] = {0, 1, 0, -1};
    const char *de[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};
    int n, m;
    const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    inline bool is_in(int r, int c){
      return r >= 0 && r < n && c >= 0 && c < m;
    }
    
    struct Node{
      int id, val;
      bool operator < (const Node &p) const{
        return val < p.val;
      }
    };
    vector<Node> v1, v2;
    
    int main(){
      cin >> n;
      int sum1 = 0, sum2 = 0;
      for(int i = 1; i <= n; ++i){
        scanf("%d", &m);
        v1.push_back((Node){i, m});
        sum1 += m;
      }
      for(int i = 1; i <= n; ++i){
        scanf("%d", &m);
        v2.push_back((Node){i, m});
        sum2 += m;
      }
      sort(v1.begin(), v1.end());
      sort(v2.begin(), v2.end());
      if(sum1 > sum2) for(int i = 0; i < n; ++i) printf("%d %d
    ", v1[i].id, v2[n-i-1].id);
      else  for(int i = 0; i < n; ++i) printf("%d %d
    ", v1[n-i-1].id, v2[i].id);
    
      return 0;
    }
    

      

  • 相关阅读:
    4 构建Mysql+heartbeat+DRBD+LVS集群应用系统系列之Lvs为Mysql-slave做负载均衡
    3 构建Mysql+heartbeat+DRBD+LVS集群应用系统系列之heartbeat的搭建
    2 构建Mysql+heartbeat+DRBD+LVS集群应用系统系列之MySql的搭建
    1 构建Mysql+heartbeat+DRBD+LVS集群应用系统系列之DRBD的搭建
    Python
    Python
    Tools
    DevOps
    Tools
    Tools
  • 原文地址:https://www.cnblogs.com/dwtfukgv/p/6789625.html
Copyright © 2011-2022 走看看