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  • servlet:共享资源造成的线程冲突

    一,由于servlet是单实例的类,在每个新客户端访问时创建一个新的线程,并在这个线程上调用Servlet的service方法,因此service方法内如果访问了同一个资源的话,就有可能引发线程安全问题。

    例:

    1,使用一个简单的登陆页面提交用户名,密码

    <%@ page language="java" import="java.util.*" contentType="text/html; charset=utf-8"%>
    <%
    String path = request.getContextPath();
    String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
    %>
    
    <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
    <html>
      <head>
        <base href="<%=basePath%>">
        
        <title>My JSP 'login.jsp' starting page</title>
        
        <meta http-equiv="pragma" content="no-cache">
        <meta http-equiv="cache-control" content="no-cache">
        <meta http-equiv="expires" content="0">    
        <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
        <meta http-equiv="description" content="This is my page">
        <!--
        <link rel="stylesheet" type="text/css" href="styles.css">
        -->
    
      </head>
      
      <body>
        <h1>登陆</h1>
       <hr>
       <form action="test.do" name="loginform" method="post">
       <table>
       <tr>
       <td>用户名</td>
       <td><input type="text" name="username"/></td>
       </tr>
       <tr>
       <td>密码</td>
       <td><input type="password" name="password"/></td>
       </tr>
       <tr>
       <td colspan="2"><input type="submit" value="登陆"/></td>
       </tr>
       </table>
       </form>
      </body>
    </html>

    2,创建一个servlet文件

    在servlet中创建两个全局变量用于接收用户名和密码

    例:

    package aaa;
    
    import java.io.IOException;
    import java.io.PrintWriter;
    
    import javax.servlet.ServletException;
    import javax.servlet.http.HttpServlet;
    import javax.servlet.http.HttpServletRequest;
    import javax.servlet.http.HttpServletResponse;
    
    public class Ddd extends HttpServlet {
    
        /**
         * Constructor of the object.
         */
        public Ddd() {
            super();
        }
    
        /**
         * Destruction of the servlet. <br>
         */
        public void destroy() {
            super.destroy(); // Just puts "destroy" string in log
            // Put your code here
        }
    
        /**
         * The doGet method of the servlet. <br>
         *
         * This method is called when a form has its tag value method equals to get.
         * 
         * @param request the request send by the client to the server
         * @param response the response send by the server to the client
         * @throws ServletException if an error occurred
         * @throws IOException if an error occurred
         */
        public void doGet(HttpServletRequest request, HttpServletResponse response)
                throws ServletException, IOException {
    
            response.setContentType("text/html");
            PrintWriter out = response.getWriter();
            out.println("<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">");
            out.println("<HTML>");
            out.println("  <HEAD><TITLE>A Servlet</TITLE></HEAD>");
            out.println("  <BODY>");
            out.print("    This is ");
            out.print(this.getClass());
            out.println(", using the GET method");
            out.println("  </BODY>");
            out.println("</HTML>");
            out.flush();
            out.close();
        }
    
        /**
         * The doPost method of the servlet. <br>
         *
         * This method is called when a form has its tag value method equals to post.
         * 
         * @param request the request send by the client to the server
         * @param response the response send by the server to the client
         * @throws ServletException if an error occurred
         * @throws IOException if an error occurred
         */
        String Username;
        String Password;
        public void doPost(HttpServletRequest request, HttpServletResponse response)
                throws ServletException, IOException {
                Username=request.getParameter("username");
                Password=request.getParameter("password");
                Thread a=new Thread(){
                    public void run(){
                        try {
                            //延迟4秒突出线程冲突
                            Thread.sleep(4000);
                            
                        } catch (InterruptedException e) {
                            // TODO Auto-generated catch block
                            e.printStackTrace();
                        }
                    }
                };
                request.setAttribute("user", this.Password+""+this.Username);
                request.getRequestDispatcher("index.jsp").forward(request, response);
            
        }
    
        /**
         * Initialization of the servlet. <br>
         *
         * @throws ServletException if an error occurs
         */
        public void init() throws ServletException {
            // Put your code here
        }
    
    }

    3,创建一个接收页面显示用户名和密码

    例:

    <%@ page language="java" import="java.util.*" contentType="text/html; charset=utf-8"%>
    <%
    String path = request.getContextPath();
    String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
    %>
    
    <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
    <html>
      <head>
        <base href="<%=basePath%>">
        
        <title>My JSP 'index.jsp' starting page</title>
        <meta http-equiv="pragma" content="no-cache">
        <meta http-equiv="cache-control" content="no-cache">
        <meta http-equiv="expires" content="0">    
        <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
        <meta http-equiv="description" content="This is my page">
        <!--
        <link rel="stylesheet" type="text/css" href="styles.css">
        -->
      </head>
      
      <body>
        <h1>
        <%String a=(String)request.getAttribute("user");
        out.print(a);
         %>
        </h1><br>
      </body>
    </html>

    如果同时打开多个登陆页面进行登陆会造成servlet的线程冲突

    3,解决方法:

    可以通过解决java多线程的冲突的方式进行解决

    synchronized(this){
                Username=request.getParameter("username");
                Password=request.getParameter("password");
                Thread a=new Thread(){
                    public void run(){
                        try {
                            //延迟4秒突出线程冲突
                            Thread.sleep(4000);
                            
                        } catch (InterruptedException e) {
                            // TODO Auto-generated catch block
                            e.printStackTrace();
                        }
                    }
                };
            }

    通过在共享的代码块上锁解决

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  • 原文地址:https://www.cnblogs.com/dybe/p/8040015.html
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