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  • Leetcode 200.岛屿的数量

    Leetcode 200 岛屿的数量:

    DFS利用函数调用栈保证了检索顺序,

    BFS则需要自己建立队列,把待检索对象按规则入队。

    class Solution {  // DFS解法,8ms/10.7MB,99.7% / 92%
    public:
    
        /**
        * row,col: 坐标,以0开始.
        * 用row和col,而不是x,y. 否则容易写成grid[x][y],顺序不对!!
        */
        void dfs_set_zero(vector<vector<char>>& grid, int row, int col) {
            int n_rows = grid.size();
            if (!n_rows) return;
            int n_cols = grid[0].size();
            if (!n_cols) return;
            
            if (row<0 || row>=n_rows || col<0 || col>=n_cols) return;
            
            if (grid[row][col] == '1') {
                grid[row][col] = '0';
                dfs_set_zero(grid, row-1, col);
                dfs_set_zero(grid, row+1, col);
                dfs_set_zero(grid, row, col-1);
                dfs_set_zero(grid, row, col+1);
            }
        }
    
        int numIslands(vector<vector<char>>& grid) {
            int result = 0;
            for (int i=0; i<grid.size(); ++i) {
                for (int j=0; j<grid[0].size(); ++j) {
                    if (grid[i][j] == '1') {
                        result++;
                        dfs_set_zero(grid, i, j);
                    }
                }
            }
            return result;
        }
    };
    
    
    class Solution {  // BFS解法,12ms/11MB, 96.9% / 69.4%
    public:
        queue<pair<int,int>> q;
        
        void bfs_set_zero(vector<vector<char>>& grid) {
            int n_rows = grid.size();
            if(!n_rows) return;
            int n_cols = grid[0].size();
            if(!n_cols) return;
            
            while (!q.empty()) {
                auto pos = q.front();
                q.pop();
                //if (grid[pos.first][pos.second] == '1') {
                    grid[pos.first][pos.second] = '0';
                    if (pos.first-1>=0 && grid[pos.first-1][pos.second] == '1')
                        q.emplace(pos.first-1,pos.second);
                    if (pos.first+1<n_rows && grid[pos.first+1][pos.second] == '1')
                        q.emplace(pos.first+1,pos.second);
                    if (pos.second-1>=0 && grid[pos.first][pos.second-1] == '1')
                        q.emplace(pos.first,pos.second-1);
                    if (pos.second+1<n_cols && grid[pos.first][pos.second+1] == '1')
                        q.emplace(pos.first,pos.second+1);
                //}
            }
        }
        
        int numIslands(vector<vector<char>>& grid) {
            int result = 0;
            for (int i=0; i<grid.size(); i++) {
                for (int j=0; j<grid[0].size(); j++) {
                    if (grid[i][j] == '1') {
                        result++;
                        //q.push(make_pair(i,j));
                        q.emplace(i,j);  // 使用emplace而非push,constructed in-place
                                             // 其实这种方式和 q.push( {i,j} );是相同的(右值引用),详见 “C++11的初始化方式”https://blog.csdn.net/K346K346/article/details/55194246
                        bfs_set_zero(grid);
                    }
                }
            }
            return result;
        }
    };
    
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  • 原文地址:https://www.cnblogs.com/dylanchu/p/11326423.html
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