zoukankan      html  css  js  c++  java
  • 499

     What's The Frequency, Kenneth? 
    #include <stdio.h>
    
    main()
    {
      int i;
      char *suffix[]= { "st", "nd", "rd" };
      char *item[]= { "Unix" , "cat", "sed", "awk", "grep", "ed", "vi"};
     
      printf("In the beginning, there was nothing.
    ");
      for (i= 0; i < 7; i++)
        printf("And on the %d%s day, God created %s. And it was good.
    ",
               i + 1, (i < 3) ? suffix[i] : "th", item[i]);
    }

    But then God saw that vi led people into temptation. Instead of choosing the righteous ways of make,dbx, and RCS, people used long command lines, printf(), and tape backups.

    So God decreed, ``I see that Engineers have thus defiled my vi. And so, I shall create emacs, an editormore powerful than words. Further, for each instantiation vi hitherto, the Engineer responsible shalt performPenance. And lo, the Penance wilt be painful; there will be much wailing and gnushingof teeth. The Engineerwill read many lines of text. For each line of text, the Engineer must tell me which letters occur the most frequently.''

    ``I charge you all with My Golden Rule: 'Friends shalt not let friends use vi'.''

    Input and Output

    Each line of output should contain a list of letters that all occured with the highest frequency in the corresponding input line, followed by the frequency.

    The list of letters should be an alphabetical list of upper case letters followed by an alphabeticallist of lower case letters.

    Sample Input

    When riding your bicycle backwards down a one-way street, if the
    wheel falls of a canoe, how many ball bearings does it take to fill
    up a water buffalo?
    Hello Howard.

    Sample Output

    e 6
    al 7
    a 3
    Hlo 2
    #include<stdio.h>
    #include<string.h>
    int max(int *a)
    {
    	int i,max=0;
    	for(i=0;i<52;i++)
    		if(a[i]>max) max=a[i];
    	return max;
    }
    int main(void)
    {
    	char a[100]={0};
    
    	while((gets(a))!=NULL)
    	{
    		int count[52]={0},i;
    		for(i=0;i<strlen(a);i++)
    		{
    			if(a[i]<='z'&&a[i]>='a')
    				count[a[i]-'a'+26]++;
    			else if(a[i]<='Z'&&a[i]>='A')
    				count[a[i]-'A']++;
    		}
    		for(i=0;i<52;i++)
    			if(count[i]==max(count))
    			{
    				if(i<26)
    					putchar(i+'A');
    				else
    					putchar(i+'a'-26);
    			}
    			printf(" %d
    ",max(count));
    	}
    	return 0;
    }


  • 相关阅读:
    记 · 佛系青年 · 嗯我百度了下
    【CSS】452- 浏览器解析 CSS 样式的过程
    记 · 平安夜 · 平安平安平安
    【Vuejs】451- Vue CLI 首屏优化技巧
    【网站发布】前端自习课
    【CSS】450- 温故而知我不懂的CSS
    【CSS】449- CSS第四级选择器
    RabbitDemo —— Topic
    RabbitDemo —— Fanout
    RabbitDemo —— Direct
  • 原文地址:https://www.cnblogs.com/dyllove98/p/3148114.html
Copyright © 2011-2022 走看看