Problem:
Implement the following operations of a queue using stacks.
- push(x) -- Push element x to the back of queue.
- pop() -- Removes the element from in front of queue.
- peek() -- Get the front element.
- empty() -- Return whether the queue is empty.
Example:
MyQueue queue = new MyQueue();
queue.push(1);
queue.push(2);
queue.peek(); // returns 1
queue.pop(); // returns 1
queue.empty(); // returns false
Notes:
- You must use only standard operations of a stack -- which means only push to top, peek/pop from top, size, and is empty operations are valid.
- Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
- You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
思路:
使用两个栈,入栈和出栈。当元素插入队列时,将元素放入入栈。如果要删除或者返回队头元素,因为队头元素位于入栈的底部,所以需要将入栈中的元素依次放入出栈,则出栈中的元素顺序就和队列顺序相同了,后面插入的元素继续放入入栈,直到出栈中的元素都弹出时再重复上述操作。
Solution (C++):
stack<int> input, output;
/** Initialize your data structure here. */
MyQueue() {
}
/** Push element x to the back of queue. */
void push(int x) {
input.push(x);
}
/** Removes the element from in front of queue and returns that element. */
int pop() {
int x = peek();
output.pop();
return x;
}
/** Get the front element. */
int peek() {
if (output.empty()) {
while (!input.empty()) {
output.push(input.top());
input.pop();
}
}
return output.top();
}
/** Returns whether the queue is empty. */
bool empty() {
return input.empty() && output.empty();
}
性能:
Runtime: 0 ms Memory Usage: 6.6 MB
思路:
Solution (C++):
性能:
Runtime: ms Memory Usage: MB