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  • Exponential notation

    Exponential notation

    You are given a positive decimal number x.

    Your task is to convert it to the "simple exponential notation".

    Let x = a·10b, where 1 ≤ a < 10, then in general case the "simple exponential notation" looks like "aEb". If b equals to zero, the part "Eb" should be skipped. If a is an integer, it should be written without decimal point. Also there should not be extra zeroes in a and b.

    Input

    The only line contains the positive decimal number x. The length of the line will not exceed 106. Note that you are given too large number, so you can't use standard built-in data types "float", "double" and other.

    Output

    Print the only line — the "simple exponential notation" of the given number x.

    Examples
    Input
    16
    Output
    1.6E1
    Input
    01.23400
    Output
    1.234
    Input
    .100
    Output
    1E-1
    Input
    100.
    Output
    1E2
    分析:这种题要多注意细节!
    代码:
    #include <bits/stdc++.h>
    using namespace std;
    int n,m,cnt,len,l,r,now;
    string a,ans;
    int main()
    {
        int i,j,k,t;
        cin>>a;
        len=a.length();
        //找小数点;
        for(now=0;now<len&&a[now]!='.';now++);
        //找左端点和右端点;
        if(a[l]=='.')l++;if(a[r]=='.')r--;
        for(l=0;a[l]=='0';l++);
        if(a[l]=='.')for(l++;a[l]=='0';l++);
        for(r=len-1;a[r]=='0';r--);
        if(a[r]=='.')for(r--;a[r]=='0';r--);
     
        ans+=a[l];
        if(r!=l){
            ans+='.';
            for(i=l+1;i<=r;i++)if(a[i]!='.')ans+=a[i];
        }
        cnt=now-(l+1);
        if(l+1>now)cnt++;
        cout<<ans;
        if(cnt)cout<<"E"<<cnt;
        cout<<endl;
        //system("pause");
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/dyzll/p/5672472.html
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