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  • [Leetcode] Wildcard Matching

    Implement wildcard pattern matching with support for '?' and '*'.

    '?' Matches any single character.
    '*' Matches any sequence of characters (including the empty sequence).
    
    The matching should cover the entire input string (not partial).
    
    The function prototype should be:
    bool isMatch(const char *s, const char *p)
    
    Some examples:
    isMatch("aa","a") → false
    isMatch("aa","aa") → true
    isMatch("aaa","aa") → false
    isMatch("aa", "*") → true
    isMatch("aa", "a*") → true
    isMatch("ab", "?*") → true
    isMatch("aab", "c*a*b") → false

    碉堡了,可以用动规,但是如果存储n*m的表的话会爆内存,可以用2*m的表存,也可以回溯法,存储star的位置,后面不匹配的话就回退到star的位置重新匹配。

     1 class Solution {
     2 //if strlen is used, then it will be TLE
     3 //iteration based solution
     4 public:
     5     bool isMatch(const char *s, const char *p) {
     6         bool star = false;
     7         const char *starPos = NULL;
     8         const char *savePos = NULL;
     9         while (*s != '') {
    10             if (*p == '?') {
    11                 ++p; ++s;
    12             } else if (*p == '*') {
    13                 while (*p == '*') ++p;
    14                 star = true;
    15                 starPos = p;
    16                 savePos = s;
    17             } else {
    18                 if (*p == *s) {
    19                     ++p; ++s;
    20                 } else {
    21                     if (star) {
    22                         s = ++savePos;
    23                         p = starPos;
    24                     } else {
    25                         return false;
    26                     }
    27                 }
    28             }
    29         }
    30         while (*p == '*') ++p;
    31         return (*s == '') && (*p == '');
    32     }
    33 };
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  • 原文地址:https://www.cnblogs.com/easonliu/p/3694775.html
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