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  • js 获取某年的某天是第几周

     1 /**
     2  * 判断年份是否为润年
     3  *
     4  * @param {Number} year
     5  */
     6 function isLeapYear(year) {
     7     return (year % 400 == 0) || (year % 4 == 0 && year % 100 != 0);
     8 }
     9 /**
    10  * 获取某一年份的某一月份的天数
    11  *
    12  * @param {Number} year
    13  * @param {Number} month
    14  */
    15 function getMonthDays(year, month) {
    16     return [31, null, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31][month] || (isLeapYear(year) ? 29 : 28);
    17 }26 /**
    27  * 获取某年的某天是第几周
    28  * @param {Number} y
    29  * @param {Number} m
    30  * @param {Number} d
    31  * @returns {Number}
    32  */
    33 function getWeekNumber(y, m, d) {
    34     var now = new Date(y, m - 1, d),
    35         year = now.getFullYear(),
    36         month = now.getMonth(),
    37         days = now.getDate();
    38     //那一天是那一年中的第多少天
    39     for (var i = 0; i < month; i++) {
    40         days += getMonthDays(year, i);
    41     }
    42 
    43     //那一年第一天是星期几
    44     var yearFirstDay = new Date(year, 0, 1).getDay() || 7;
    45 
    46     var week = null;
    47     if (yearFirstDay == 1) {
    48         week = Math.ceil(days / yearFirstDay);
    49     } else {
    50         days -= (7 - yearFirstDay + 1);
    51         week = Math.ceil(days / 7) + 1;
    52     }
    53 
    54     return week;
    55 }
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  • 原文地址:https://www.cnblogs.com/eboke/p/4313432.html
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