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  • LeetCode OJ

    这道题就是找规律啊!!!

    想想啊,11和10是可以连续的,那么10和11也是可以连续的。

    下面是AC代码:

     1  /**
     2       * The gray code is a binary numeral system where two successive values differ in only one bit.
     3       * Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.
     4       * For example, given n = 2, return [0,1,3,2]. Its gray code sequence is:
     5       * 00 - 0
     6       * 01 - 1
     7       * 11 - 3
     8       * 10 - 2
     9       * Note:
    10       * For a given n, a gray code sequence is not uniquely defined.
    11       * For example, [0,2,3,1] is also a valid gray code sequence according to the above definition.
    12       * For now, the judge is able to judge based on one instance of gray code sequence. Sorry about that.
    13       * Solution : find the rule!!!!
    14       * @param n
    15       * @return
    16       */
    17      public ArrayList<Integer> grayCode(int n) {
    18          ArrayList<Integer> r = new ArrayList<Integer>();
    19          r.add(0);
    20          if(n == 0)
    21              return r;
    22          r.add(1);
    23          if(n == 1)
    24              return r;
    25          for(int m = 1;m<n;m++){
    26              int cur_size = r.size();
    27              int base = (int) Math.pow(2, m);
    28              for(int i = cur_size - 1;i>=0;i--){
    29                  r.add(r.get(i)+base);
    30              }
    31          }
    32          return r;
    33      }
    有问题可以和我联系,bettyting2010#163 dot com
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  • 原文地址:https://www.cnblogs.com/echoht/p/3717895.html
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