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  • Python编程:从入门到实践—列表

    访问列表中的元素

    >>> bicycles = ['trek','cannondale','redline','specialized']
    >>> print(bicycles)
    ['trek', 'cannondale', 'redline', 'specialized']
    >>> print(bicycles[0])
    trek
    >>> print(bicycles[-1])
    specialized
    >>> print(bicycles[0].title())
    Trek

    修改、添加和删除元素

    修改列表元素

    >>> motorcycles = ['honda','yamaha','suzuki']
    >>> print(motorcycles)
    ['honda', 'yamaha', 'suzuki']
    >>> motorcycles[0] = 'ducati'
    >>> print(motorcycles)
    ['ducati', 'yamaha', 'suzuki']

    在列表中添加元素

    >>> motorcycles = []
    >>> motorcycles.append('honda')
    >>> motorcycles.append('yamaha')
    >>> motorcycles.append('suzuki')
    >>> print(motorcycles)
    ['honda', 'yamaha', 'suzuki']

    在列表中插入元素

    >>> motorcycles = ['honda','yamaha','suzuki']
    >>> motorcycles.insert(0,'ducati')
    >>> print(motorcycles)
    ['ducati', 'honda', 'yamaha', 'suzuki']

    从列表中删除元素

    >>> motorcycles = ['honda','yamaha','suzuki']
    >>> print(motorcycles)
    ['honda', 'yamaha', 'suzuki']
    >>> del motorcycles[0]
    >>> print(motorcycles)
    ['yamaha', 'suzuki']

    使用方法pop()删除元素

    方法pop()删除列表末尾的元素,并可以使用它

    >>> motorcycles = ['honda','yamaha','suzuki']
    >>> popped_motorcycle = motorcycles.pop()
    >>> print(motorcycles)
    ['honda', 'yamaha']
    >>> print(popped_motorcycle)
    suzuki

    应用:

    >>> motorcycles = ['honda','yamaha','suzuki']
    >>> last_owned = motorcycles.pop()
    >>> print("The last motorcycles I owned was a " + last_owned.title() + ".")
    The last motorcycles I owned was a Suzuki.

    弹出列表中任何位置处的元素:

    >>> motorcycles = ['honda','yamaha','suzuki']
    >>> first_owned = motorcycles.pop(0)
    >>> print('The first motorcycle I owned was a ' + first_owned.title() + '.')
    The first motorcycle I owned was a Honda.
    >>> print(motorcycles)
    ['yamaha', 'suzuki']

    每当使用pop(),被弹出的元素就不再在列表中了。

    使用值删除元素

    >>> motorcycles = ['honda','yamaha','suzuki','ducati']
    >>> print(motorcycles)
    ['honda', 'yamaha', 'suzuki', 'ducati']
    >>> motorcycles.remove('ducati')
    >>> print(motorcycles)
    ['honda', 'yamaha', 'suzuki']

    使用remove()从列表中删除的元素,也可以接着使用它的值。

    >>> motorcycles = ['honda','yamaha','suzuki','ducati']
    >>> print(motorcycles)
    ['honda', 'yamaha', 'suzuki', 'ducati']
    >>> too_expensive = 'ducati'
    >>> motorcycles.remove(too_expensive)
    >>> print(motorcycles)
    ['honda', 'yamaha', 'suzuki']
    >>> print(" A " + too_expensive.title() + " is too expensive for me.")

    A Ducati is too expensive for me.

    方法remove()只删除第一个指定的值。如果要删除的值可能在列表中出现多次,就需要使用循环来判断是否删除了所有这样的值。

    组织索引

    >>> cars = ['bmw','audi','toyoda','subaru']
    >>> print(cars)
    ['bmw', 'audi', 'toyoda', 'subaru']
    >>> cars.sort()
    >>> print(cars)
    ['audi', 'bmw', 'subaru', 'toyoda']
    方法sort()永久性地修改了列表元素的排列顺序,cars按字母顺序排列

    倒序排序方式:

    >>> cars = ['bmw','audi','toyoda','subaru']
    >>> cars.sort(reverse=True)
    >>> print(cars)
    ['toyoda', 'subaru', 'bmw', 'audi']

    使用函数sorted()对列表进行临时排序

    >>> cars = ['bmw','audi','toyoda','subaru']
    >>> print("Here is the original list:",cars)
    Here is the original list: ['bmw', 'audi', 'toyoda', 'subaru']
    >>> print("Here is the original list: ",sorted(cars))
    Here is the original list:
    ['audi', 'bmw', 'subaru', 'toyoda']
    >>> print(" Here is the original list:",cars)

    Here is the original list: ['bmw', 'audi', 'toyoda', 'subaru']

    倒着打印列表

    >>> cars = ['bmw','audi','toyoda','subaru']
    >>> print(cars)
    ['bmw', 'audi', 'toyoda', 'subaru']
    >>> cars.reverse()
    >>> print(cars)
    ['subaru', 'toyoda', 'audi', 'bmw']

    方法reverse()永久性地修改列表元素的排列顺序

    确定列表长度:

    >>> cars = ['bmw','audi','toyoda','subaru']
    >>> len(cars)

    操作列表

     遍历整个列表:

    >>> magicians = ['alice','david','carolina']
    >>> for magician in magicians:
    ... print(magician)
    ...
    alice
    david
    carolina

    >>> for magician in magicians:
    ... print(magician.title() + ",that was a great trick!")
    ...
    Alice,that was a great trick!
    David,that was a great trick!
    Carolina,that was a great trick!

     在for循环之后执行一些操作

    在for循环后面,没有缩进的代码只执行一次,而不会重复执行,Python根据缩进代码行与前一个代码的关系

    #!/usr/bin/env python
    # -*- encoding:utf-8 -*-
    magicians = ['alice','elon','carolian']
    for magician in magicians:
    print(magician.title() + ",that was a great trick!")
    print("I can't wait to see your next trick," + magician.title() + ". ")
    print("Thank you,everyone.That was a great magic show!")

    执行结果:

    Alice,that was a great trick!
    I can't wait to see your next trick,Alice.

    Elon,that was a great trick!
    I can't wait to see your next trick,Elon.

    Carolian,that was a great trick!
    I can't wait to see your next trick,Carolian.

    Thank you,everyone.That was a great magic show!

    创建数值列表:

    >>> for value in range(1,5):
    ... print(value)
    ...
    1
    2
    3
    4

    使用range()创建列表

    将range()作为list()的参数,输出将为一个数字列表

    >>> numbers = list(range(1,5))
    >>> print(numbers)
    [1, 2, 3, 4]

    使用函数range()时,还可以指定步长,函数range()从2开始数,然后不断加2,直到达到或超过终值11

    >>> even_numbers = list(range(2,11,2))
    >>> print(even_numbers)
    [2, 4, 6, 8, 10]

    使用函数range()几乎能够创建任何需求的数字集,例如:创建一个列表,其中包含前10个整数的平方。

    >>> squares = []
    >>> for value in range(1,11):
    ... square = value ** 2
    ... squares.append(square)
    ... print(squares)
    ...
    [1]
    [1, 4]
    [1, 4, 9]
    [1, 4, 9, 16]
    [1, 4, 9, 16, 25]
    [1, 4, 9, 16, 25, 36]
    [1, 4, 9, 16, 25, 36, 49]
    [1, 4, 9, 16, 25, 36, 49, 64]
    [1, 4, 9, 16, 25, 36, 49, 64, 81]
    [1, 4, 9, 16, 25, 36, 49, 64, 81, 100]

    为了代码简洁,可不使用临时变量square

    >>> squares = []
    >>> for value in range(1,11):
    ... squares.append(value**2)
    ... print(squares)
    ...
    [1]
    [1, 4]
    [1, 4, 9]
    [1, 4, 9, 16]
    [1, 4, 9, 16, 25]
    [1, 4, 9, 16, 25, 36]
    [1, 4, 9, 16, 25, 36, 49]
    [1, 4, 9, 16, 25, 36, 49, 64]
    [1, 4, 9, 16, 25, 36, 49, 64, 81]
    [1, 4, 9, 16, 25, 36, 49, 64, 81, 100]

    对数字列表执行简单的统计计算

    >>> digits = [1,2,3,4,5,6,7,8,9,0]
    >>> min(digits)
    0
    >>> max(digits)
    9
    >>> sum(digits)
    45

    使用列表的一部分

    切片

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  • 原文地址:https://www.cnblogs.com/elontian/p/9998525.html
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